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FinnZ [79.3K]
2 years ago
11

What are the concentrations of hydroxide and hydronium ions in a solution with a pH of 8.3?

Chemistry
1 answer:
Margarita [4]2 years ago
5 0

Answer:

The hydroxide concentration is 2*10^-6 M

The hydronium concentration is 5*10^-9 M

Explanation:

Step 1: Data given

pH = 8.3

Step 2: Calculate [H+]

pH = 8.3 = -log [H+]

[H+] = 10^-8.3 = 5*10^-9 M

[H+] = [H3O+] = 5*10^-9 M

Step 3: Calculate pOH

pH + pOH = 14

pOH = 14 -pH = 14 - 8.3 = 5.7

Step 4: Calculate concentration of hydroxide

pOH = -log [OH-] = 5.7

[OH-] = 10^-5.7 = 2*10^-6 M

The hydroxide concentration is 2*10^-6 M

The hydronium concentration is 5*10^-9 M

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How many number of moles are present in 200. g of sodium bicarbonate (NaHCO3)
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You can solve this problem through dimensional analysis.

First, find the molar mass of NaHCO3.

Na = 22.99 g

H = 1.008 g

C = 12.01 g

O (3) = 16 (3) g

Now, add them all together, you end with with the molar mass of NaHCO3.

22.99 + 1.008 + 12.01 + 16(3) = 84.008 g NaHCO3. This number means that for every mole of NaHCO3, there is 84.008 g NaHCO3. In simpler terms, 1 mole NaHCO3 = 84.008 g NaHCO3.

After finding the molar mass of sodium bicarbonate, now you can use dimensional analysis to solve for the number of moles present in 200. g of sodium bicarbonate.

200. g NaHCO_3 * \frac{1 mole NaHCO_3}{84.008 g NaHCO_3}

Cross out the repeating units which are g NaHCO3, and the remaining unit is mole NaHCO3

200.  * 1 = 200

200/ 84.008 = 2.38

Notice how there are only 3 sig figs in the answer. This is because the given problem only gave three sig figs.

Your final answer is 2.38 mol NaHCO3.

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