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VARVARA [1.3K]
3 years ago
9

What is the mass of the 3.7 mol pbo2?

Chemistry
1 answer:
serious [3.7K]3 years ago
5 0
239,2 g/mol x 3,7 mol = 885,04 g
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How many moles of methane (CH4) could be made from 4.6 moles of hydrogen?
DENIUS [597]

Answer:

Number of moles of methane form = 2.3 mol

Explanation:

Given data:

Number of moles of Hydrogen = 4.6 mol

Number of moles of methane form = ?

Solution:

Chemical equation:

C + 2H₂     →   CH₄

Now we will compare the moles of methane with hydrogen from balance chemical equation.

                     H₂              :           CH₄

                       2              :             1

                     4.6             :            1/2×4.6 = 2.3 mol  

Form 3.6 moles of hydrogen 2.3 moles of methane can be formed.

6 0
3 years ago
In a titration of 0.35 M HCl and 0.35 M NaOH, how much NaOH should be added to 45.0 ml of HCl to completely neutralize the acid?
Bezzdna [24]
It would be the same amount. So, 45 ml of NaOH is required to be added to the 45 ml of HCI to neutralize the acid fully. Here is a brief calculation:

Firstly, here is your formula: M(HCI) x V(HCI) = M(NaOh) x V(NaOH) 
With the values put in: 0.35 x 45 = 0.35 x V(NaOH) 
= 45 ml. 
There is 45 ml of V(NaOH)

Let me know if you need anything else. :)

           - Dotz
6 0
3 years ago
What are sister chromatids
Pavel [41]
Sister chromatids are two identical copies of a single chromosome that are connected by a centromere. They occur as a result of a chromosome that  duplicated during the S phase of the cell cycle.
4 0
3 years ago
A piston chamber filled with ideal gas is kept in a constant-temperature bath at 25.0°C. The piston expands from 25.0 mL to 75.0
larisa [96]

Answer : The work done by the system is, 2.2722 J

Explanation :

The expression used for work done in reversible isothermal expansion will be,

w=nRT\ln (\frac{V_2}{V_1})

where,

w = work done = ?

n = number of moles of gas  = 0.00100 mole

R = gas constant = 8.314 J/mole K

T = temperature of gas  = 25^oC=273+25=298K

V_1 = initial volume of gas  = 25 mL

V_2 = final volume of gas  = 75 mL

Now put all the given values in the above formula, we get:

w=0.00100mole\times 8.314J/moleK\times 298K\times \ln (\frac{75}{25})

w=2.722J

Therefore, the work done by the system is, 2.2722 J

8 0
3 years ago
How many moles of water h2o are present in 75.0 g h2o?
nikklg [1K]
4.17 moles. Good luck! :)
7 0
3 years ago
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