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blondinia [14]
3 years ago
14

Triangles K L P and Q M N are shown. Triangle Q M N is slightly higher than triangle K L P and side Q M connects to side K P. Po

int M is at the midpoint of K P. Sides K L and Q N are congruent. Angles K L P and Q N M are congruent. Angles K P L and Q M N are both right angles. Is there a series of rigid transformations that could map TriangleKLP to TriangleQNM? If so, which transformations? No, TriangleKLP and TriangleQNM are congruent but TriangleKLP cannot be mapped to TriangleQNM using a series rigid transformations. No, TriangleKLP and TriangleQNM are not congruent. Yes, TriangleKLP can be reflected across the line containing KP and then translated so that P is mapped to M. Yes, TriangleKLP can be rotated about P and then translated so that L is mapped to N.
Mathematics
2 answers:
sergiy2304 [10]3 years ago
8 0

Answer:

the answer is C

Step-by-step explanation:

Dafna1 [17]3 years ago
5 0

Answer: C

Step-by-step explanation:

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AB has coordinates A(-5,9) and B(7,- 7). Points P, Q, and I are collinear
VMariaS [17]

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\overline{QT}

Step-by-step explanation:

We want to find the coordinates of a certain point C(x,y) such that C divides A(x_1,y_1) and B(x_2,y_2) in the ratio m:n=3:2

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The y-coordinate is given by:

y=\frac{my_2+ny_1}{m+n}

AB has coordinates A(-5,9) and B(7,- 7)

We substitute the values to get:

x=\frac{3*7+2*-5}{3+2}

x=\frac{21-10}{5}

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Therefore C has coordinates  (\frac{11}{5},-\frac{3}{5})

The line segment that contains C is \overline{QT}

See attachment.

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¯¯¯ , BD¯¯¯¯¯ , and CD¯¯¯¯¯ are angle bisectors of the sides of △ABC . CF=8 m and CD=17 m. What is DE ?
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