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EastWind [94]
3 years ago
10

...............................................

Physics
1 answer:
Bingel [31]3 years ago
8 0

Answer:

...............................................What is your question?

Explanation:

...............................................

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A toy car is moving along with 0.40 joules of kinetic energy if it’s speed is double then it’s new kinetic energy will be ?
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Answer: .8

Explanation: because .40×2 =.8

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3 years ago
ANSWER TRUE OR FALSE FOR EACH OF THESE.
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5 0
4 years ago
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What is the potential energy of two electrons that are separated by a distance of 3.5 x 10^-11m ?
Simora [160]

Answer:

6.58×10⁻¹⁸ J

Explanation:

Applying

E = kq²/r.................. Equation 1

Where E = potential energy, q = charge on each electron, r = distance between the electron, k = coulomb's constant.

From the question,

Given: r = 3.5×10⁻¹¹ m,

Constant: q = 1.6×10⁻¹⁹ C, k = 8.99×10⁹ Nm²/C²

Substitute these values into equation 1

E = (1.6×10⁻¹⁹)²(8.99×10⁹)/(3.5×10⁻¹¹)

E = 6.58×10⁻¹⁸ J

4 0
3 years ago
An 80-kg bungee jumper jumps off a bridge. Rubber bungee cords act as a large spring attaching the jumper to the bridge. A bear
inysia [295]

Answer:

The force is F_b =  216 \  N

Explanation:

From the question we are told that

   The  mass of the bungee jumper is  m  = 80 kg

    The spring constant is  k =  20 \  N/ m

    The extension of the rubber bungee cords is  x = 50 m

Generally the weight of the jumper is

      W =  m *  g

=>   W =  80 *  9.8

=>   tex]W =  784  \  N  [/tex]

Generally  the returning force of the rubber bungee cords is mathematically represented as

      F  =  k  *  x

=>     F  =  20   * 50

=>     F  =  1000 \  N

The force to be applied by the bear is

    F_b =  F -  W

=>    F_b =  100 -  784

=>  F_b =  216 \  N

6 0
3 years ago
PLEASE HELP! A river current has a velocity of 5km/h relative to the shore, and a boat moves in the same direction as the curren
Usimov [2.4K]

add the river's velocity to the boat's velocity

5+ 5 = 10 km/h

Hope this helps!

5 0
4 years ago
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