Answer:
a = 3.21 10⁻⁸ m / s²
, The correct answer is E
Explanation:
For this exercise we will use Newton's second law, where the force is the gravitational attraction force, the attached diagram shows the forces and their components in a horizontal and vertical coordinate system, due to the symmetry of the equilateral triangle the horizontal components be annulled and the two vertical components add up; let's write Newton's education for the vertical axis (Y)
2
= m a
Let's use trigonometry to find the components
sin 60 =
/ F
= F sin60
2 F sin60 = m a
The gravitational force equation is
F = G m M / r
The mass of the entire sphere is equal to m = M and the distance between the spheres is the side of the equilateral triangle
F = G m² / L²
We replace
2 (G m² / L²) sin60 = m a
a = 2 G m / L² sin 60
Let's calculate
a = 6.67 10⁻¹¹ 50 / 0.30² sin 60
a = 3.21 10⁻⁸ m / s²
The correct answer is E
Answer:
Within atoms and molecules electrons can only have certain values for their energy:
We say that energy levels are discretized. We can easily observe the differences between some of these levels by analyzing the light emitted by electrons when moving from one level to another less energetic. The emitted photons have exactly the energy difference between the levels, and as we know that the energy of a photon is:
E = hc / λ
where h is Planck's constant, c is the speed of light and λ is the wavelength.
Explanation:
Each atom is capable of emitting or absorbing electromagnetic radiation, although only at some frequencies that are characteristic of each of the different chemical elements.
If, through the supply of heat energy, a certain element is stimulated in its gas phase, its atoms emit radiation at certain frequencies of the visible, which constitute its emission spectrum.
Thus, the so-called Kirchoff's Law is fulfilled, which indicates that every element absorbs radiation in the same wavelengths in which it emits it. The absorption and emission spectra thus turn out to be the negative one of the other.
Since the spectrum, both emission and absorption, is characteristic of each element, it serves to identify each of the elements of the periodic table, by simple visualization and analysis of the position of the absorption or emission lines in its spectrum.
These characteristics are manifested whether it is a pure element or combined with other elements, so a fairly reliable identification procedure is obtained.
The option that BEST correctly defines the scientific method is option C.
Answer:
D. A light wave can travel without a medium.
Explanation:
Light wave can be defined as an electromagnetic wave that do not require a medium of propagation for it to travel through a vacuum of space where no particles exist.
On the other hand, mechanical waves such as sound are highly dependent on matter for their propagation and transmission.
This ultimately implies that, the properties which makes a light wave different from all mechanical waves is that, a light wave can travel without a medium of propagation.
<h2>
Hey There!</h2><h2>_____________________________________</h2><h2>
Answer:</h2><h2>_____________________________________</h2><h3>DATA:</h3>
Angle of projection = θ(theta) =
Initial Velocity =
= ![2x10^3](https://tex.z-dn.net/?f=2x10%5E3)
Acceleration due to gravity = g = 9.8 m/s^2
Vertical Velocity =
= ?
Horizontal Velocity =
= ?
Range of the Shell = R = ?
Maximum Height = H = ?
<h2>_____________________________________</h2><h3>SOLUTION:</h3>
Vertical Velocity is given by,
θ
![V_Y = (2x10^3)xCos(30)](https://tex.z-dn.net/?f=V_Y%20%3D%20%282x10%5E3%29xCos%2830%29)
![V_Y = (2x10)^3x(0.866)\\\\V_Y = 1732.05 \frac{m}{s}](https://tex.z-dn.net/?f=V_Y%20%3D%20%282x10%29%5E3x%280.866%29%5C%5C%5C%5CV_Y%20%3D%201732.05%20%5Cfrac%7Bm%7D%7Bs%7D)
Horizontal Velocity is given by,
θ
![V_X = (2x10^3)xSin(30)\\\\V_X = (2000)x(0.5)\\\\V_X = 1000\frac{m}{s}](https://tex.z-dn.net/?f=V_X%20%3D%20%282x10%5E3%29xSin%2830%29%5C%5C%5C%5CV_X%20%3D%20%282000%29x%280.5%29%5C%5C%5C%5CV_X%20%3D%201000%5Cfrac%7Bm%7D%7Bs%7D)
Range is given by,
R =
Sin2θ
Horizontal Velocity is given by,
<h2>
![H = \frac{V_0^2Sin^2(theta)}{2g}\\\\\\H= \frac{(2x10^3)^2xSin(30)^2}{2x10}\\\\\\H= \frac{(4x10^6)x(0.25)}{20} \\\\H = 50000 m](https://tex.z-dn.net/?f=H%20%3D%20%5Cfrac%7BV_0%5E2Sin%5E2%28theta%29%7D%7B2g%7D%5C%5C%5C%5C%5C%5CH%3D%20%5Cfrac%7B%282x10%5E3%29%5E2xSin%2830%29%5E2%7D%7B2x10%7D%5C%5C%5C%5C%5C%5CH%3D%20%5Cfrac%7B%284x10%5E6%29x%280.25%29%7D%7B20%7D%20%5C%5C%5C%5CH%20%3D%2050000%20m)
_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2>