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Lana71 [14]
4 years ago
14

What it the area of a 10*9 square

Mathematics
2 answers:
Elodia [21]4 years ago
7 0
If you take 10*9 that is 90.  If all the sides are 90, then you do 90*90 and that equals 8,100
bixtya [17]4 years ago
4 0
The answer is 90 aqnd     the others are lying

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Write the equation of the line in slope intercept form that passes through the two points: (1,-6) and (-3,2)
tatiyna

Answer:

y = -2x - 4

Step-by-step explanation:

Formula is y = mx + b where m is the slope and b is the y-intercept

(1, -6) (-3, 2)

\frac{-6-2}{1-(-3)}=\frac{-8}{4} =-2

The slope is -2

y = -2x + b

So let's find b, insert 2 for y and -3 for x to find b

2 = -2(-3) + b

2 = 6 + b

Subtract 6 from both sides to get b alone

-4 = b

We found what b equals (the y-intercept), which is -4

So, the equation is y = -2x - 4

Hope this helps and pls do mark me brainliest:)

5 0
3 years ago
What is the solution to this system of linear equations? 2x + y = 1 3x – y = –6
jenyasd209 [6]
2x + y = 1 . . . (1)
3x - y = -6 . . . (2)

(1) + (2) => 5x = -5 => x = -5/5 = -1

From (1), 2x - 1 = 1 => 2x = 1 + 1 = 2 => x = 2/2 = 1

x = 1, y = -1
3 0
4 years ago
Read 2 more answers
Which best completes the following sentence? Triangles are congruent if they have the same
bagirrra123 [75]

Answer:

same sides and angles

Step-by-step explanation:

6 0
3 years ago
Olivia will attend Blake University this fall. Tuition for one year is $11,350. Olivia plans to earn $1,500 at her work-study jo
g100num [7]

Answer:

4650 add 1500+1800+3400 u get 6700

then you get the tuition cost then subtract it by 6700

your final answer is 4650 dollar

8 0
3 years ago
Determine the values of the unlabeled parts of the triangle.
____ [38]

Answer:

∠Q = 63.4º, PQ = 2, QO = 4.47

Step-by-step explanation:

A triangle is a polygon with three sides and three angles. There are different types of triangles such as the equilateral triangle, isosceles triangle, scalene triangle, right angled triangle.

Triangle POQ is a right angled triangle because ∠P = 90°. Also, ∠O = 26.6°.

Therefore in ΔPOQ: ∠P + ∠O + ∠Q = 180° (sum of angles in a triangle).

90 + 26.6 + ∠Q = 180

∠Q + 116.6 = 180

∠Q = 180 - 116

∠Q = 63.4°

We can find PQ and QO using sine rule. Sine rule for ΔPOQ is given as:

\frac{PO}{sin Q}= \frac{PQ}{sinO}= \frac{QO}{sin P}\\\\Finding\ PQ  :\\\\\frac{PO}{sin Q}= \frac{PQ}{sinO}\\\\\frac{4}{sin(63.4)} =\frac{PQ}{sin(26.6)}\\\\PQ= \frac{4}{sin(63.4)} *sin(26.6)\\\\PQ = 2\\\\Also\ finding\ QO:\\\\\frac{PO}{sin Q}= \frac{QO}{sinP}\\\\\frac{4}{sin(63.4)} =\frac{QO}{sin(90)}\\\\QO=\frac{4}{sin(63.4)} *sin(90)\\\\QO = 4.47

4 0
3 years ago
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