Answer:
a
Step-by-step explanation:
![\sqrt[4]{144a^{12}b^{3}} = \sqrt[4]{4^{2}*3^{2}a^{12}b^{3}}=\\= \sqrt[4]{2^{4}*3^{2}a^{12}b^{3}}=2a^{3}\sqrt[4]{3^{2}b^{3}} =\\}=2a^{3}\sqrt[4]{9b^{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B144a%5E%7B12%7Db%5E%7B3%7D%7D%20%3D%20%5Csqrt%5B4%5D%7B4%5E%7B2%7D%2A3%5E%7B2%7Da%5E%7B12%7Db%5E%7B3%7D%7D%3D%5C%5C%3D%20%5Csqrt%5B4%5D%7B2%5E%7B4%7D%2A3%5E%7B2%7Da%5E%7B12%7Db%5E%7B3%7D%7D%3D2a%5E%7B3%7D%5Csqrt%5B4%5D%7B3%5E%7B2%7Db%5E%7B3%7D%7D%20%3D%5C%5C%7D%3D2a%5E%7B3%7D%5Csqrt%5B4%5D%7B9b%5E%7B3%7D%7D)
Rearranging the first equation gives:
Substituting this into the other equation gives:
If x=-1:
So
x=-1, y=-5
Answer:
You have to translate these sentences into expressions. I am not going to solve all of these because if I explain one/two problems to you, you'll get the hang of it. Seven more than three times a number: 7+3x; Five times a number decreased by six: 5x-6
Step-by-step explanation:
Why? We don't know what number that is, so we can put any variable like (x, y, z, a, b, etc.). Three times a number is simply that number times 3. In this case we would input: 3*x, or 3x. 7 more than that number is 3x+7. Five times a number decreased by six: 5x-6 . Remember: it is simply 5*x which simplifies to 5x. Decreased is take away, so take away 6, and get 5x-6
Key words: Quotient: the result after dividing two/or more numbers; Product: the result after multiplying two/ or more numbers; Decreased: take away (Example: x decreased by 7=x-7)
I hope you understand!! It is very simple after you start to get the hang of it!!
