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3 years ago

Standard twist-on wire connectors are not suitable for terminating or splicing aluminum or copper-clad aluminum conductors.

Physics

1 answer:

Rainbow [258]3 years ago

4 0

Answer:

True.

Explanation:

Twist-on wire connectors are a sort of electrical conduit used only to fasten two or more small tension (or extra-low tension) electrical conductors.They are also called wire nuts, wire connectors or cone connectors( because of their conical shape). They are not suitable for for terminating or splicing aluminum or copper-clad aluminum conductors.

Hence the above statement is true.

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The momentum of the moving depends on which among the given factors?

Tasya [4]

Explanation:

<h3>mass and velocity</h3>

,,,,,

4 0

2 years ago

Ilya and Anya each can run at a speed of 7.50 mph and walk at a speed of 4.00 mph. They set off together on a route of length 5.

r-ruslan [8.4K]

Answer:

$T_A=0.93hours$

$S_A=5.23mph$

$T_l=0.87hour$

Explanation:

From the question we are told that

Run speed of Ilya and Anya $S_r=7.50mph$

Walk speed of Ilya and Anya $S_w=4.00mph$

Total distance $T_d=5.00miles$

Anya Walks 1/2d and runs 1/2d

ilya walks 1/2t and runs 1/2d

Generally the distance walked by Ilay k is mathematically given by

Since ilya walks 1/2t and runs 1/2t

Therefore

$\frac{k}{4}=\frac{5-k}{7.5}$

$k=1.7miles$

Therefore llay runing distance is m

$m=5-1.7\\m=3.3mile$

a)Generally the Time walked by Anya $T_A$ is mathematically given by

Anya Walks 1/2d and runs 1/2d

Therefore

$t=\frac{2.5}{4.}$

$t_1=0.6hours$

$t=\frac{2.5}{7.5}$

$t_2=0.33hours$

$T_A=0.6+0.33\\$

$T_A=0.93hours$

b)Generally the average speed of Anya S_A is mathematically given as

$S_A=\frac{Distance}{T_t}$

$S_A=\frac{5.0}{0.93}$

$S_A=5.23mph$

Generally the time taken b y llay $T_l$ is mathematically given by

$T_l=2t$

$T_l=2*(\frac{1.7}{4})$

$T_l=0.87hour$

3 0

3 years ago

The term yoga means which of the following:

hjlf

The answer is A: to relax & meditate

8 0

3 years ago

Read 2 more answers

A ball thrown straight up takes 1.89s to reach a height of 41.6m.

yulyashka [42]

Answer:

Explanation:

average velocity is 41.6/1.89 = 22.0 m/s

initial velocity u is

22.0 = (u + u - 9.81(1.89))/2

44.0 = 2u - 18.5

62.56 = 2u

u = 31.3 m/s

max height is

v² = u² + 2as

s = (v² - u²) / 2a

s = (0² - 31.3²) / (2(-9.81)) = 49.9 m

49.9 = 41.6 = 8.27 m higher

In process numbers have been rounded to 3 s.d. for reporting purposes.

8 0

3 years ago

Four charges of equal magnitude q = 2.16 µC are situated as shown in the diagram below. If d = 0.88 m, find the electric potenti

Triss [41]

Answer:

<em>The total potential (magnitude only) is 11045.45 V</em>

Explanation:

<u>Electric Potential </u>

The total electric potential at location A is the sum of all four individual potentials produced by the charges, including the sign since the potential is a scalar magnitude that can be computed by

$\displaystyle V=\frac{kq}{r}$

Where k is the Coulomb's constant, q is the charge, and r is the distance from the charge. Let's find the potential of the rightmost charge:

$\displaystyle V_1=\frac{9\cdot 10^{9}\times -2.16\cdot 10^{-6}}{0.88}=-22090.91\ V$

The potential of the leftmost charge is exactly the same as the above because the charges and distances are identical

$V_2=-22090.91\ V$

The potential of the topmost charge is almost equal to the above computed, is only different in the sign:

$V_3=+22090.91\ V$

The bottom charge has double distance and the same charge, thus the potential's magnitude is half the others':

$\displaystyle V_4=\frac{9\cdot 10^{9}\times 2.16\cdot 10^{-6}}{1.76}=+11045.45 \ V$

The total electric potential in A is

$V=-22090.91\ V-22090.91\ V+22090.91\ V+11045.45 \ V$

$V=-11045.45 \ V$

The total potential (magnitude only) is 11045.45 V

8 0

3 years ago