Answer:
Option A. 57.14 Ω
Explanation:
From the question given above, the following data were obtained:
Resistor 1 (R₁) = 100 Ω
Resistor 2 (R₂) = 400 Ω
Resistor 3 (R₃) = 200 Ω
Equivalent Resistor (Rₚ) =?
The equivalent resistor in the above circuit can be obtained as follow:
1/Rₚ = 1/R₁ + 1/R₂ + 1/R₃
1/Rₚ = 1/100 + 1/400 + 1/200
Find the least common multiple (lcm) of 100, 400 and 200. The result is 400. Divide 400 by 100, 200 and 400 respectively and multiply the result with the numerator as shown
1/Rₚ = (4 + 1 + 2)/400
1/Rₚ = 7/400
Invert
Rₚ = 400/7
Rₚ = 57.14 Ω
Answer:
40watts
Explanation:
Given parameters:
Work done = 3000J
Time = 75s
Unknown:
Power generated = ?
Solution:
Power is the rate at which work is done;
Power =
Now, insert the parameters and solve;
Power = = 40watts
Answer:
d= 794.4 cmExplanation:
Given that
Speed ,V= 286 km/h
V=79.44 m/s
Given that time ,t= 100 ms
t= 0.1 s
We know that ( if acceleration is zero)
Distance = Speed x time
d= V t
Now by putting the values in the above equation
d = 79.44 x 0.1 m
d= 7.944 m
We know that 1 m = 100 cm
d= 794.4 cm
The gap between the two flasks is partially evacuated of air creating a near vacuum which significantly reduces heat transfer by conduction or convection
Using kinematic equation s=ut + 1/2 at^2(u = initial velocity=0, s=120m, t= 6.32s), 120 = 0(t) + 1/2 a(6.32)^2. a = 120x2/(6.32)^2 = 6m/s^2.