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vaieri [72.5K]
2 years ago
12

Which of the following is not dimensionally correct? E=mc2 B. vf=vi+at S=vt2 D. S=1/2 at2

Physics
1 answer:
Elodia [21]2 years ago
5 0

Answer:

s=vt2 just simplify all into metric units first

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A football player who weighs 550 N stands indoors wearing her football boots. The boot’s
EleoNora [17]

Answer:

183333 Pa

Explanation:

The weight of the football player is : 550 N ,thus the force the player exerts on the floor is 550 N

The area of blades in contact with the floor is = 30cm² = 0.003 m²

Pressure = Force / Area

Pressure = 550 / 0.003

Pressure = 183333 Pa

3 0
2 years ago
What is the momentum of a 1200 kg car traveling with a speed of 27 m/s (60 mph)?
serious [3.7K]

Answer:

This is your answer

Explanation:

Actually I took this from go ogle

3 0
2 years ago
The earth rotates every 86,160 seconds. What is the tangential speed (in m/s) at Livermore (Latitude 37.6819° measured up from e
Lena [83]

Answer:

The tangential speed at Livermore is approximately 284.001 meters per second.

Explanation:

Let suppose that the Earth rotates at constant speed, the tangential speed (v), measured in meters per second, at Livermore (37.6819º N, 121º W) is determined by the following expression:

v = \left(\frac{2\pi}{\Delta t}\right)\cdot R \cdot \sin \phi (1)

Where:

\Delta t - Rotation time, measured in seconds.

R - Radius of the Earth, measured in meters.

\phi - Latitude of the city above the Equator, measured in sexagesimal degrees.

If we know that \Delta t = 86160\,s, R = 6.371\times 10^{6}\,m and \phi = 37.6819^{\circ}, then the tangential speed at Livermore is:

v = \left(\frac{2\pi}{86160\,s} \right)\cdot (6.371\times 10^{6}\,m)\cdot \sin 37.6819^{\circ}

v\approx 284.001\,\frac{m}{s}

The tangential speed at Livermore is approximately 284.001 meters per second.

4 0
3 years ago
A load of 45N attached to a spring that is hanging vertically stretches the spring 0.14m. What is the spring constant?
Vesna [10]
6.3 That Would be the I answer I think but Check on Google For the formula
6 0
2 years ago
How long will it take for a car to accelerate to come to a stop if it is traveling at 20m/s and the car has a maximum decelerati
Pachacha [2.7K]
When the car comes to a stop, the final velocity must be 0 m/s.
Since the car js decelerating in a forward direction, acceleration must be negative.

final v = initial v + a•t
0 = 20 + (-6)t
t = 3.33s
5 0
3 years ago
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