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Step2247 [10]
3 years ago
8

PLEASE HELP ME

Mathematics
2 answers:
Mama L [17]3 years ago
6 0

Answer:

45 units

Step-by-step explanation:

iogann1982 [59]3 years ago
4 0

Since both are on the line y=10, the distance between the points is their difference in x-coordinates: 15 - (-30) = 45 units.

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AXY Zand AABCare similar triangles. Given the dimensions shown in the diagram, what is the
Lady bird [3.3K]

Answer:

3.528

Step-by-step explanation:

First, you need to determine the scale factor. Divide one side in the larger triangle by the corresponding side in the smaller triangle. For example, 8/2. This would give you a scale factor of 2. Then you can reverse the process with the dimensions you need to get the area. The height of the larger triangle is 3.36, so to find the height of the smaller one, you divide it by 2, or the scale factor, to get the height of the smaller triangle which is 1.68. Next, you can solve for area of triangle using a=bh/2, so 4.2*1.68/2=a = 3.528.

6 0
3 years ago
Michael breeds chickens and ducks.
hodyreva [135]
Let c=cost of chicken and d=cost of duck; 50c+30d=550 and 44c+36d=532.
So 5c+3d=55, 11c+9d=133.
Therefore 15c+9d=165, subtracting 11c+9d=133 we get: 4c=32 so c=8.
5c+3d=40+3d=55, so 3d=15 and d=5.
Cost of chicken is $8 and cost of duck is $5.
4 0
3 years ago
Read 2 more answers
Solve for x (8x-27) (3x=58)
melomori [17]

Answer:

x=3.565

Step-by-step explanation:


5 0
3 years ago
A photo is 4 inches wide. It is placed inside a frame with a border that is x inches wide. The total width of the photo and the
Anna [14]
4 + 2x = 7
2x = 7 - 4 = 3
x = 3/2 = 1.5 inches
5 0
3 years ago
A car valued at £18000 at the start of 2017, depreciated in value by 5% each year for 3 years. How much did it lose in value ove
Anna11 [10]

<u>Answer:</u>

The amount lost over the 3 years s 2567.25£  

<u>Explanation:</u>

$\mathrm{F}=\mathrm{I} \times\left(1-\left(\frac{r}{100}\right)\right)^{\mathrm{n}}$

where F = final value after n years

I = initial value of the car in 2017 = £18000 (given)

Since the value is depreciated 5% every year for 3 years,

r = percentage rate of depreciation = 5% (given)

n = 3 years

Substituting these values in formula, we get

$\mathrm{F}=18000 \times\left(1-\frac{5}{100}\right)^{3}$

= $18000 \times\left(\frac{95}{100}\right)^{3}$

 = 15432.75£ which is the value of the car after 3 years

Finally 18000-15432.75 = 2567.25£ is the amount lost over this period.  

6 0
3 years ago
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