Answer:
A rectangle is a quadrilateral that has congruent diagonals. The rectangle is a convex quadrilateral because of two diagonals which lie in the interior of the rectangle.
You do 390/100 = 180/x then 390×X=390X
180×100=18000
390X=18000
390X÷390=X
18000÷390=46.15384615=46%
<em>So</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em> </em><em>of</em><em> </em><em>option</em><em> </em><em>D</em><em>.</em>
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>.</em><em>.</em>
<em>Additional</em><em> </em><em>Information</em><em>:</em>
<em>The</em><em> </em><em>second</em><em> </em><em>components</em><em> </em><em>of</em><em> </em><em>a</em><em> </em><em>relation</em><em> </em><em>is</em><em> </em><em>called</em><em> </em><em>range</em><em> </em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>be</em><em> </em><em>helpful</em><em> </em><em>to</em><em> </em><em>you</em><em>. </em><em>.</em>
To find the slope between two coordinates, you use the formula:
m = y2 - y1/x2 - x1
If coordinate A is (-2, 5) and coordinate B is (3, -4), then:
y2 = -4
y1 = 5
x2 = 3
x1 = -2
So, just substitute the points into the formula.
m = -4 - 5/3 - (-2)
m = -9/5
The slope of the line is -9/5.
Answer:
The smallest possible perimeter of the triangle, rounded to the nearest tenth is 72.4 in
Step-by-step explanation:
The Triangle Inequality Theorem states that the sum of any 2 sides of a triangle must be greater than the measure of the third side
Let
x ------> the length of the remaining side
Applying the triangle inequality theorem
1) x+x > 30
2x > 30
x > 15 in
The perimeter is equal to
P=30+2x
<em>Verify each case</em>
1) For P=41.0 in
substitute in the formula of perimeter and solve for x
41.0=30+2x
2x=41.0-30
x=5.5 in
Is not a solution because the value of x must be greater than 15 inches
2) For P=51.2 in
substitute in the formula of perimeter and solve for x
51.2=30+2x
2x=51.2-30
x=10.6 in
Is not a solution because the value of x must be greater than 15 inches
3) For P=72.4 in
substitute in the formula of perimeter and solve for x
72.4=30+2x
2x=72.4-30
x=21.2 in
Could be a solution because the value of x is greater than 15 inches
4) For P=81.2 in
substitute in the formula of perimeter and solve for x
81.2=30+2x
2x=81.2-30
x=25.6 in
Could be a solution because the value of x is greater than 15 inches
therefore
The smallest possible perimeter of the triangle, rounded to the nearest tenth is 72.4 in
