Answer:
The answer is C: has at least three oxidation states.
Explanation:
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Answer:
The standard entropy or reaction ΔS° =+324.6J/mol.K
Explanation:
The reaction is
2H2O(l) → 2H2(g) + O2(g)
Standard Molar Entropies of Selected Substances at 298 K are
Substance S∘ (J/mol⋅K)
H2(g) 130.6
O2(g) 205.0
H2O(g) 188.8
H2O(l) 69.9
The standard entropy of reaction will be obtained from standard entropy of formation as given below
ΔH°= 2(130.6)+(205.0)-2(69.9) (Jol/mol.K)
ΔH°=261.2+205.0-139.8
ΔH°=+324.6Jol/mol.K
No heating peanut butter does the opposite
Answer:
C20H1404 you have to write it like smaller numbers if you understand
I think the statement above is true. Benzene and its derivatives would undergo a type of substitution reaction wherein a hydrogen atom is being replaced by a substituent but the stable aromatic benzene ring is being regenerated at the end of the mechanism. This is called the electrophilic aromatic substitution. The hydrogen atom of the aromatic ring is being replaced as a result of the electrophilic attack on the ring. THis reaction has two steps. First, the electrophile would attack the pi electrons of the benzene ring resulting to a resonance stabilized carbocation. Then, the intermediate would be attacked by a base and it would lose a proton. The electrons would be used to form agin the pi bond restoring the ring.