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stepladder [879]
2 years ago
13

Propane is used as a fuel source on many barbeque grills. What is undergoing reduction during the burning of propane while grill

ing
Chemistry
1 answer:
Anni [7]2 years ago
8 0

Answer:

Oxygen

Explanation:

because oxygen is used when making and sustaining a fire.

I think this seems like something is missing from the question

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How do the elephants help to maintain the population of birds that you can see perched on their backs?
Zolol [24]

You need to answer this question because we don't do your

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2 years ago
What are some problems an astronaut might experience while traveling in space?
Jlenok [28]

Answer:

The environment of space is lethal without appropriate protection: the greatest threat in the vacuum of space derives from the lack of oxygen and pressure, although temperature and radiation also pose risks. The effects of space exposure can result in ebullism, hypoxia, hypocapnia, and decompression sickness.

7 0
3 years ago
How many moles are in 68.5g of KOH?
Dafna11 [192]

Answer: It has to be 56.10564

Explanation:1 grams KOH to mol = 0.01782 mol

10 grams KOH to mol = 0.17824 mol

20 grams KOH to mol = 0.35647 mol

30 grams KOH to mol = 0.53471 mol

40 grams KOH to mol = 0.71294 mol

50 grams KOH to mol = 0.89118 mol

100 grams KOH to mol = 1.78235 mol

200 grams KOH to mol = 3.5647

8 0
3 years ago
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Elements are pure substances made up of _____.
mel-nik [20]
Elements are pure substances made up of molecules
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3 years ago
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Balance each of the following examples of heterogeneous equilibria and write each Kc expression. Then calculate the value of Kc
marysya [2.9K]

Explanation:

1) 2 Al(s) + 2 NaOH(aq) + 6 H_2O(l) \longleftrightarrow 2 Na[Al(OH)_4](aq) + 7 H_2(g)

Kc=\frac{[Na[Al(OH)_4]]^2*[H_2]^7}{[NaOH]^2}

The Kc for the reverse reaction is the inverse of the Kc of the reaction:

Kc_{reverse}=\frac{1}{Kc}=\frac{1}{11}=0.091

2) H_2O(l) + SO_3(g) \longleftrightarrow H_2SO_4 (aq)

Kc=\frac{[H_2SO_4]}{[SO_3]^2}

The Kc for the reverse reaction is the inverse of the Kc of the reaction:

Kc_{reverse}=\frac{1}{Kc}=\frac{1}{0.0123}=81.3

3)  P_4(s) + 3 O_2(g) \longleftrightarrow P_4O_6(s)

Kc=\frac{1}{[O_2]^3}

The Kc for the reverse reaction is the inverse of the Kc of the reaction:

Kc_{reverse}=\frac{1}{Kc}=\frac{1}{1.56}=0.641

5 0
3 years ago
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