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stepladder [879]
2 years ago
13

Propane is used as a fuel source on many barbeque grills. What is undergoing reduction during the burning of propane while grill

ing
Chemistry
1 answer:
Anni [7]2 years ago
8 0

Answer:

Oxygen

Explanation:

because oxygen is used when making and sustaining a fire.

I think this seems like something is missing from the question

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The solubility of calcium oxalate, CaC2O4, in pure water is 4.8 × 10‑5 moles per liter. Cal­culate the value of Ksp for silver c
inn [45]

Answer:

2.3 × 10⁻⁹

Explanation:

Step 1: Write the reaction for the solution of calcium oxalate

CaC₂O₄(s) ⇄ Ca²⁺(aq) + C₂O₄²⁻(aq)

Step 2: Make an ICE chart

We can relate the molar solubility (S) with the solubility product constant (Ksp) through an ICE chart.

        CaC₂O₄(s) ⇄ Ca²⁺(aq) + C₂O₄²⁻(aq)

I                                0                 0

C                              +S               +S

E                                S                 S

The solubility product constant is:

Ksp = [Ca²⁺] × [C₂O₄²⁻] = S² = (4.8 × 10⁻⁵)² = 2.3 × 10⁻⁹

4 0
3 years ago
When particles are added volume will
Alecsey [184]
Volume will increase. As you put particles back together then it would make it a lot heavier, giving it more volume. 
8 0
4 years ago
Read 2 more answers
What is the relative molecular mass (mr) of ammonia, formula NH3?
egoroff_w [7]

Answer:

APROXIMENTLY 17

Explanation:

lol i remebered from science class

7 0
3 years ago
The planet Mercury takes 176 days to do one spin around its pole. Compared to the Earth,
Tanya [424]

Answer:

The sun would appear to move more slowly across Mercury's sky.

Explanation:

This is because, the time it takes to do one spin or revolution on Mercury is 176 days (which is its period), whereas, the time it takes to do one spin or revolution on the Earth is 1 day.

Since the angular speed ω = 2π/T where T = period

So on  Mercury, T' = 176days = 176 days × 24 hr/day × 60 min/hr × 60 s/min = ‭15,206,400‬ s

So, ω' = 2π/T'

= 2π/15,206,400‬ s

= 4.132 × 10⁻⁷ rad/s

So on  Earth, T" = 1 day = 1 day × 24 hr/day × 60 min/hr × 60 s/min = ‭‭86,400‬ s

So, ω" = 2π/T"

= 2π/86,400‬ s

= 7.272 × 10⁻⁵ rad/s

Since ω' = 4.132 × 10⁻⁷ rad/s << ω" = 7.272 × 10⁻⁵ rad/s, <u>the sun would appear to move more slowly across Mercury's sky.</u>

4 0
3 years ago
Three isotopes of argon occur in nature. Calculate the average atomic mass of argon given the following relative atomic masses a
Volgvan

Answer:

whats the question

Explanation:

6 0
3 years ago
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