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satela [25.4K]
3 years ago
6

What am I supposed to do using the Science Textbook? Please help!!!!!!!See the picture above.

Chemistry
1 answer:
baherus [9]3 years ago
6 0
It looks like part of the Periodic Table. Do you have to write down the most common Periodic Table elements? If so, then that's probably what you should do.
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If you have 3.48 x 1023 formula units of Lead (II) Permanganate, what is its mass?
Tanya [424]

Answer:

\large \boxed{\text{257 g}}

Explanation:

We can convert the formula units to moles and then use the molar mass to find the mass.

1. Moles of Pb(MnO₄)₂

n = 3.48 \times 10^{23}\text{ formula units} \times \dfrac{\text{1 mol}}{6.022 \times 10^{23}\text{ formula units}} = \text{0.5779 mol}

 

2. Mass of Pb(MnO₄)₂

\text{Mass} = \text{0.5779 mol} \times \dfrac{\text{445.07 g}}{\text{1 mol u}} = \text{257 g}\\\\\text{The mass of lead(II) permanganate is $\large \boxed{\textbf{257 g}}$}

4 0
4 years ago
Determine the freezing point of 0.368 kg of H2O with 11.85 g of C2H5OH where the kf is 1.86 C/m.
saveliy_v [14]
We will use the formula for freezing point depression :

but first, we need to get the molality m of the solution:

- molality m = moles of C2H5OH / mass of water Kg

 when moles of C2H5OH = mass of C2H5OH/ molar mass of C2H5OH

                                            = 11.85 g / 46 g/mol
                                 
                                           = 0.258 moles

and when we have the mass of water Kg = 0.368 Kg

so, by substitution on the molality formula:

∴ molality m = 0.258 moles / 0.368 Kg

                     = 0.7 mol/Kg

and when C2H5OH is a weak acid so, there is no dissociation ∴ i = 1

and when Kf is given = 1.86 C/m

so by substitution on ΔTf formula:

when ΔTf = i Kf m

∴ ΔTf = 1 * 1.86C/m * 0.7mol/Kg

          = 1.302 °C

5 0
3 years ago
When boiling water what does adding salt do
Troyanec [42]

Adding salt increases the boiling point of the water, which would make it so the water takes longer to get to a boiling point.

4 0
3 years ago
How many liters of C3H6O are present in a sample weighing 25.6 grams?
lawyer [7]

To Find :

Number of moles of C₃H₆O present in a sample weighing 25.6 grams.

Solution :

Molecular mass of C₃H₆O is :

M = (6×12) + (6×1) + (16×1) grams

M = 94 grams/mol

We know, number of moles of 25.6 grams of C₃H₆O is :

n = \dfrac{Given \ Mass \ Of \ C_3H_6O }{Molar\ Mass \ Of \ C_3H_6O }\\\\n = \dfrac{25.6}{94}\ mole\\\\n = 0.27 \ mole

Hence, this is the required solution.

4 0
3 years ago
What is happening to the temperature of the substance BEFORE AND AFTER the phase changes?
Neporo4naja [7]
First off, you must realize that the phase changes are marked by the points B and D on the graph. They are level because all of the energy (or heat) being added is being consumed by the physical process. So The temperature is increasing before the phase change, and after the phase change. The moments before and after are represented by points A, C, and E.
5 0
3 years ago
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