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satela [25.4K]
3 years ago
6

What am I supposed to do using the Science Textbook? Please help!!!!!!!See the picture above.

Chemistry
1 answer:
baherus [9]3 years ago
6 0
It looks like part of the Periodic Table. Do you have to write down the most common Periodic Table elements? If so, then that's probably what you should do.
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Which form of energy is directly related to the measure of the average kinetic energy of the particles in a substance?
timama [110]

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thermal energy

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How does e=mc^2 connect to quarks
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Which of these expressions are correct variations of the Combined Gas Law?
mafiozo [28]

Answer:

Both

Explanation:

The combined gas law is also known as the general gas law.

From the ideal gas law we assume that n = 1;

So;

              PV  = nRT

 and then;

                  \frac{P_{1}V_{1}  }{T_{1} }  = \frac{P_{2}V_{2}  }{T_{2} }

   If we cross multiply;

                P₁V₁T₂   = P₂V₂T₁

  So;

         T₁ = T_{2} \frac{P_{1}V_{1}  }{P_{2} V_{2} }

Also;

         V₂  = V_{1} \frac{P_{1} T_{2} }{P_{2} T_{1} }

So from the choices both are correct

3 0
3 years ago
The graphic shows two isomers of a chemical compound with molecular formula C5H11NO2. Which type of isomers are these? A. struct
-BARSIC- [3]
The two compounds shown indeed have tha same molecular formula, C5 H11 NO2. One of the molecules has a group NH2 and a group COOH, the other molecule has a NOO group, that makes that the two isomers have a completely different structure, with the atoms arranged in a completely different order. <span>This kind of isomers fits in the definition of structural isomers, so the answer is structural isomers.</span>
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3 years ago
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Electromagnetic radiation with a wavelength of 525 nm appears as green light to the human eye. The energy of one photon of this
Sedbober [7]

<u>Answer:</u> The energy of one photon of the given light is 3.79\times 10^{-19}J

<u>Explanation:</u>

To calculate the energy of one photon, we use Planck's equation, which is:

E=\frac{hc}{\lambda}

where,

\lambda = wavelength of light = 525nm=5.25\times 10^{-7}m        (Conversion factor:  1m=10^9nm  )

h = Planck's constant = 6.625\times 10^{-34}J.s

c = speed of light = 3\times 10^8m/s

Putting values in above equation, we get:

E=\frac{6.625\times 10^{-34}J.s\times 3\times 10^8m/s}{5.25\times 10^{-7}mm}\\\\E=3.79\times 10^{-19}J

Hence, the energy of one photon of the given light is 3.79\times 10^{-19}J

3 0
3 years ago
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