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alexira [117]
3 years ago
10

A radioactive isotope has a half-life of 2 minutes. How many total minutes will it take for 100-g of the isotope to get to just

6.25-g remaining
Chemistry
2 answers:
sergij07 [2.7K]3 years ago
6 0

Answer:

8 minutes

Explanation:

G(g)                 T(min)

100 --------------- 0

50-------------------2

25 -------------------4

12.5  ---------------  6

6.25 ----------------8

     another    way:

100/6.25 = 16

  16 = 2⁴       ( 4 half lives)    

Each half life is 2 minutes

so 4 half lives will be 8 minutes

andreev551 [17]3 years ago
4 0

Answer:

It would take 12 minutes.

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What is the molarity of a solution containing 8.0 moles of solute in 120mL of solution?
Nataliya [291]
Answer:
200/3 M which is approximately equal to 66.6667 M

Explanation:
Molarity is defined as the number of moles of solute per liter of solution.

It can be calculated as follows:
molarity =  \frac{number of moles of solute}{liters of solution}

We are given that:
number of moles of solute = 8 moles
volume of solution = 120 ml = 0.12 liters

Substitute with the givens in the above equation to get the molarity as follows:
molarity = \frac{8}{0.12} =  \frac{200}{3} = 66.6667 M

Hope this helps :)
3 0
3 years ago
If parents wanted to pick their child's traits like hair color, gender, eye color, what would doctors have to do?
kap26 [50]

Answer:

Nothing

Explanation:

I would say this because the parents are picking the baby's traits and they make all the decisions. And i guess the doctor would have to follow the traits, if i'm right  i tried

5 0
3 years ago
Chlorine (Cl) is 76% chlorine-35 and 24% chlorine-37. Determine the average atomic mass of chlorine. Show/Explain work.
Flura [38]

Answer:

Average atomic mass of chlorine is 35.48 amu.

Explanation:

Given data:

Percent abundance of Cl-35 = 76%

Percent abundance of Cl-37 = 24%

Average atomic mass = ?

Solution:

Average atomic mass  = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)  / 100

Average atomic mass  = (76×35)+(24×37) /100

Average atomic mass =  2660 + 888 / 100

Average atomic mass  = 3548/ 100

Average atomic mass = 35.48 amu

Average atomic mass of chlorine is 35.48 amu.

4 0
2 years ago
HELLO MAY I GET HELP AGAIN?
Novay_Z [31]

Answer:

( c ) sunlight.

Explanation:

the leaves are closer to the sunlight they require.

4 0
2 years ago
The pKa of lactic acid is 3.9. A lactate buffer will be useful from pH values ________. The pKa of lactic acid is 3.9. A lactate
Vedmedyk [2.9K]

Answer:

Explanation:

The usefulness of a buffer is its ability to resist changes in pH when small quantities of base or acid are added to it. This ability is the consequence of having both the conjugate base and the weak acid present in solution which will consume the added base or acid.  

This capacity is lost if the ratio of the concentration of conjugate base to the concentration of weak acid differ by an order of magnitude. Since  buffers having ratios differing by more will have their pH driven by either the weak acid or its conjugate base .

From the Henderson-Hasselbach equation we have that

pH = pKa + log [A⁻]/[HA]

thus

0.1 ≤  [A⁻]/[HA] ≤ 10

Therefore the log of this range is -1 to 1, and the pH will have a useful range of within +/- 1 the pKa of the buffer.

Now we are equipped to answer our question:

pH range = 3.9 +/- 1 = 2.9 through 4.9

7 0
3 years ago
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