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alexira [117]
3 years ago
10

A radioactive isotope has a half-life of 2 minutes. How many total minutes will it take for 100-g of the isotope to get to just

6.25-g remaining
Chemistry
2 answers:
sergij07 [2.7K]3 years ago
6 0

Answer:

8 minutes

Explanation:

G(g)                 T(min)

100 --------------- 0

50-------------------2

25 -------------------4

12.5  ---------------  6

6.25 ----------------8

     another    way:

100/6.25 = 16

  16 = 2⁴       ( 4 half lives)    

Each half life is 2 minutes

so 4 half lives will be 8 minutes

andreev551 [17]3 years ago
4 0

Answer:

It would take 12 minutes.

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Anyone know the answer
kodGreya [7K]

Answer:

a and d

Explanation:

a bromine and the calcium atom loses two elections

6 0
3 years ago
Which of the following has the greatest electronegativity difference between the bonded atoms? a. A strong acid made of hydrogen
NARA [144]

Answer: Option (d) is the correct answer.

Explanation:

Electronegativity value of hydrogen is 2.2.

Electronegativity value of chlorine is 3.16.

Electronegativity value of carbon is 2.55.

Electronegativity value of oxygen is 3.44.

Electronegativity value of nitrogen is 3.04.

Electronegativity value of sodium is 0.93.

Electronegativity value of iodine is 2.66.

Therefore, calculate the electronegativity difference between the bonded atoms as follows.

  • Electronegativity difference of HCl = Electronegativity value of chlorine - electronegativity value of hydrogen

                                                          = 3.16 - 2.2

                                                          = 0.96

  • Electronegativity difference of CO = Electronegativity value of oxygen - electronegativity value of carbon

                                                          =  3.44 - 2.55

                                                          = 0.89

  • Electronegativity difference of N_{2} = Electronegativity value of nitrogen - electronegativity value of nitrogen

                                                           = 3.04 - 3.04

                                                           = 0

  • Electronegativity difference of NaI = Electronegativity value of iodine - electronegativity value of sodium

                                                          = 2.66 - 0.93

                                                          = 1.73

So, we can see that highest electronegativity difference is 1.73 and it is shown by NaI molecule.

Thus, we can conclude that a group 1 alkali metal bonded to iodide, such as NaI has the greatest electronegativity difference between the bonded atoms.

5 0
3 years ago
Read 2 more answers
(Giving brainliest if u help mee)
Degger [83]
I think it would be B
7 0
3 years ago
Read 2 more answers
Which of the following is a combustion reaction?
azamat

Answer:

A.NaOH+HCI+NaCI+H2O

Explanation:

It's a Acid-base

5 0
3 years ago
Find the mass of each of these substances? 2.40 mol NaOH
damaskus [11]
Na = 23 x 2.40 = 55.2
O = 16 x 2.40 = 38.4
H = 1 x 2.40 = 2.40

55.2 + 38.4 + 2.4 = 96

2.40 mol of NaOH = 96 amu

4 0
4 years ago
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