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3 years ago

How does surface area affect evaporation?

2 answers:

8 0

The surface area affects evaporation because the more area exposed to air allowing water to acquire more heat energy hope this helps :)

GREYUIT [131]3 years ago

3 0

An estimated value of 90% of the water in the atmosphere comes from Earth's water. Some water evaporates from the water on land, but the majority of the water vapor evaporates from the water on Earth's oceans. The ocean covers most of Earth's surface. As a result, the oceans receive most of the solar energy that reaches Earth.

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Dan bikes 10 km west and then bikes another 5 km west. What is Dan's

777dan777 [17]

C

This is because 10+5=15
15/45=0.3

4 0

2 years ago

2. Carbon-11 is a radioactive isotope of carbon. Its half-life is 10 minutes.

Annette [7]

It’s probably probably 01/16 because of the other number don’t make sense except that one

5 0

2 years ago

For the reaction shown, calculate how many grams of each product form when the following amounts of reactant completely react to

stira [4]

This may help you
You need to use some stoichiometry here. The only way to do that is if you're working in moles. Since you're given grams of Al, you can convert that moles by dividing by the molar mass. Then from looking at the coefficients in your equation, you can see that for however many moles of Al react, the same numbers of moles of Fe will be produced, but only half as many moles of Al2O3 will be produced. To go back to grams, multiply the moles of each product that you get by their molar masses!

7 0

3 years ago

How many atoms are in a 1.8 mol sample of Magnesium (Mg)?

Gnom [1K]

Answer:

1.1 × 10²⁴ atoms Mg

General Formulas and Concepts:

Atomic Structure

Moles
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Stoichiometry

Using Dimensional Analysis

Explanation:

Step 1: Define

Identify

[Given] 1.8 mol Mg

[Solve] atoms Mg

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

[DA] Set up: $\displaystyle 1.8 \ mol \ Mg(\frac{6.022 \cdot 10^{23} \ atoms \ Mg}{1 \ mol \ Mg})$
[DA] Multiply [Cancel out units]: $\displaystyle 1.08396 \cdot 10^{24} \ atoms \ Mg$

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

1.08396 × 10²⁴ atoms Mg ≈ 1.1 × 10²⁴ atoms Mg

5 0

3 years ago

Read 2 more answers

Calculate the standard reaction enthalpy for the reaction NO2(g) → NO(g) + O(g) given +142.7 kJ/mol for the standard enthalpy of

bulgar [2K]

Answer:

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

Explanation:

$O_2(g) \rightarrow \frac{2}{3}O_3(g),\Delta H^o_{1}=142.7 kJ/mol$ ..[1]

$O_2(g) \rightarrow 2 O(g),\Delta H^o_{2}=498.4 kJ/mol$ ..[2]

$NO(g) + O_3(g)\rightarrow NO_2(g) + O_2(g) ,\Delta H^o_{3} = -200 kJ/mol$ ..[3]

$NO_2(g)\rightarrow NO(g) + O(g),\Delta H^o_{4}=?$ ..[4]

Using Hess's law:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

2 × [4] = [2]- (3 ) × [1] - (2) × [3]

$2\times \Delta H^o_{4}=\Delta H^o_{2} -3\times \Delta H^o_{1}-2\times \Delta H^o_{3}$

$2\times \Delta H^o_{4}=498.4 kJ/mol-3\times 142.7 kJ/mol-2\times -200 kJ/mol$

$2\times \Delta H^o_{4}=470.3 kJ/mol$

$\Delta H^o_{4}=\frac{470.3 kJ/mol}{2}=235.15 kJ/mol$

The standard reaction enthalpy for the given reaction is 235.15 kJ/mol.

7 0

3 years ago