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2 years ago

What is the molarity of a solution prepared by dissolving 8 grams of BaCl2 in enough

Chemistry

1 answer:

olga55 [171]2 years ago

6 0

Answer:

Explanation:

molar mass of BaCl2 = 208.23

mol of BaCl2 = 8/208.22

mol of BaCl2 = 0.03841905

Molarity = 0.03841905/0.450

Molarity = 0.085 M

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morpeh [17]

Answer:

For a: The isotopic representation of iodine is $_{53}^{131}\textrm{I}$

For b: The isotopic representation of cesium is $_{55}^{137}\textrm{Cs}$

For c: The isotopic representation of strontium is $_{38}^{52}\textrm{Sr}$

Explanation:

The isotopic representation of an atom is: $_Z^A\textrm{X}$

where,

Z = Atomic number of the atom

A = Mass number of the atom

X = Symbol of the atom

For a:

We are given:

Number of neutrons = 78

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Mass number = 53 + 78 = 131

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For b:

We are given:

Number of neutrons = 82

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Mass number = 55 + 82 = 137

Thus, the isotopic representation of cesium is $_{55}^{137}\textrm{Cs}$

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We are given:

Number of neutrons = 52

Atomic number of strontium = 38 = Number of protons

Mass number = 38 + 52 = 90

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