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max2010maxim [7]
3 years ago
5

What two forces determines whether an object floats or sinks

Physics
1 answer:
svetlana [45]3 years ago
7 0

Gravity, which acts downward on the object and its buoyant force that acts upwards and is dependent on weight of the volume of water displaced by the object.  

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a student conducts an experiment to determine how the additional of salt to water affects the density of the water. the student
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The water would be because however much salt you add the water rises
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7. If F1 is the magnitude of the force exerted by the Earth on a satellite in orbit about the Earth and F2 is the magnitude of t
natita [175]

Answer:

F1 is equal to F2            

Explanation:

Here

F1 is the gravitational force exerted by the earth on the satellite.

F2 is the gravitational force exerted by the satellite on the earth.

Now these two forces are equal but opposite in nature. This is given by the Third law of motion by Newton. According to this law, when there is force exerted between two objects, one force is balanced the other force which is equal in magnitude and opposite in nature.

Thus the gravitational force of the earth exerted on the satellite is equal to the force exerted by the satellite on the earth.

Hence F1 = F2.

8 0
3 years ago
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A certain string on a piano is tuned to produce middle c (f = 261.63 hz) by carefully adjusting the tension in the string. for a
Lemur [1.5K]

Frequency and wavelength are two variables which are indirectly proportional.

They are related in the following equation:

f = c / w

Where,

<span>f = frequency    c = speed of light          w = wavelength</span>

Since c is constant, we can equate condition 1 and condition 2:

f1 w1 = f2 w2

When w2 = 3 w1, then f2 becomes:

261.63 w1 = f2 (3 w1)

Cancelling w1:

f2 = 261.63 / 3

<span>f2 = 87.21 Hz</span>

7 0
3 years ago
Two point charges, A and B, are separated by a distance of 22.0 cm . The magnitude of the charge on A is twice that of the charg
REY [17]

Answer:

1.12×10⁻⁵ C and 2.24×10⁻⁵ C.

Explanation:

From coulomb's law,

F = kAB/r².............................. Equation 1

Where F = Force exerted by each charge, A = charge at point A, B = charge at point B, r = distance of separation between the points, k = constant of proportionality.

Given: F = 47 N, r = 22 cm = 0.22 m.

Constant: k = 9.0×10⁹ Nm²/C²

Let: B = q, the A = 2q.

Substituting these values into equation 1,

47 = 9.0×10⁹(q×2q)/0.22²

47 = 18×10⁹(q²)/0.0484

q² = (47×0.0484)/(18×10⁹)

q² = 0.126×10⁻⁹

q² = 1.26×10⁻¹⁰

q = √( 1.26×10⁻¹⁰)

q = 1.12×10⁻⁵ C

The charge at point A = 2q = 2× 1.12×10⁻⁵  = 2.24×10⁻⁵ C.

Hence the charges are 1.12×10⁻⁵ C and 2.24×10⁻⁵ C.

3 0
3 years ago
Planet A takes 1 year to go around its star at an average of 1 A.U. distance. Planet B is 4 A.U. from the star. Calculate how lo
pentagon [3]

Planet Geos in orbit a distance of 1 A.U. (astronomical unit) from the star Astra has an orbital period of 1 "year." If planet Logos is 4 A.U. from Astra, how long does Logos require for a complete orbit?

TB = <span>8</span> years

7 0
4 years ago
Read 2 more answers
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