The skeletal system is a body system comprised of bone structures and tissues that help hold the body up. It also gives the body its shape - as if it was the framework. On top of that, it protects internal organs within the body.
Therefore, the skeletal system is a body system comprised of bone structures and tissues that give the body its shape and protects internal organs.
Hope this helps!
Answer:
The electric field will be decreased by 29%
Explanation:
The distance between point P from the distance z = 2.0 R
Inner radius = R/2
Outer raidus = R
Thus;
The electrical field due to disk is:
)
Similarly;
However; the relative difference is:
![\dfrac{\hat {k_a} - \hat {k_b}}{\hat {k_a} }= \dfrac{E_a -E_a + \dfrac{\sigma}{2 \varepsilon_o \Big[1 - \dfrac{2.0 \ R}{\sqrt{(2.0 \ R)^2 + (\dfrac{R}{2})^2}} \Big] } } { \dfrac{\sigma}{2 \varepsilon_o \Big [ 1 - \dfrac{2.0 \ R}{\sqrt{ (2.0 \ R)^2 + (R)^2}} \Big] }}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Chat%20%7Bk_a%7D%20-%20%5Chat%20%7Bk_b%7D%7D%7B%5Chat%20%7Bk_a%7D%20%7D%3D%20%5Cdfrac%7BE_a%20-E_a%20%2B%20%5Cdfrac%7B%5Csigma%7D%7B2%20%5Cvarepsilon_o%20%20%5CBig%5B1%20-%20%5Cdfrac%7B2.0%20%5C%20R%7D%7B%5Csqrt%7B%282.0%20%5C%20R%29%5E2%20%2B%20%28%5Cdfrac%7BR%7D%7B2%7D%29%5E2%7D%7D%20%5CBig%5D%20%7D%20%7D%20%7B%20%5Cdfrac%7B%5Csigma%7D%7B2%20%5Cvarepsilon_o%20%5CBig%20%5B%201%20-%20%5Cdfrac%7B2.0%20%5C%20R%7D%7B%5Csqrt%7B%20%282.0%20%5C%20R%29%5E2%20%2B%20%28R%29%5E2%7D%7D%20%5CBig%5D%20%7D%7D)

Answer:
The impression of the image on the retina lasts for about 1/16th of a second after the removal of the object. If a burning stick of incense is revolved at a rate of more than sixteen revolutions per second, we see a circle of red light due to persistence of vision.
Explanation:
Answer:
x = 6.94 m
Explanation:
For this exercise we can find the speed at the bottom of the ramp using energy conservation
Starting point. Higher
Em₀ = K + U = ½ m v₀² + m g h
Final point. Lower
= K = ½ m v²
Em₀ = Em_{f}
½ m v₀² + m g h = ½ m v²
v² = v₀² + 2 g h
Let's calculate
v = √(1.23² + 2 9.8 1.69)
v = 5.89 m / s
In the horizontal part we can use the relationship between work and the variation of kinetic energy
W = ΔK
-fr x = 0- ½ m v²
Newton's second law
N- W = 0
The equation for the friction is
fr = μ N
fr = μ m g
We replace
μ m g x = ½ m v²
x = v² / 2μ g
Let's calculate
x = 5.89² / (2 0.255 9.8)
x = 6.94 m