20 kg who is running at a speed of 4.0 m/s jumps onto a stationary sled of mass 5.0 kg on a frozen lake. the speed at which the
child and sled begin to slide across the ice is most nearly
1 answer:
Here we can use momentum conservation as there is no external force on sled and child while he jump on sled
by momentum conservation equation


since sled and child both moves with same speed so here they both will have same final speed "v"
by solving above equation we will have
25 v = 80
v = 3.2 m/s
So they will move together with speed 3.2 m/s
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Answer:
8.8 kN
Explanation:
V = 2 m³, W = 40 kN, SG = 1.59
Bouyant force N = 1.59 * 1000 kg/m³ * 9.81 N/kg * 2 m³ = 31.2 kN
So the weight becomes 40 - 31.2 = 8.8 kN
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chemical energy into mechanical energy as well as heat.
Answer:
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Explanation: