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Basile [38]
3 years ago
12

An object is placed in a fluid and then released. Assume that the object either floats to the surface (settling so that the obje

ct is partly above and partly below the fluid surface) or sinks to the bottom. (Note that, for Parts A through D, you should assume that the object has settled in equilibrium.)
A.Consider the following statement: The magnitude of the buoyancy force is equal to the weight of fluid displaced by the object.
Under what circumstances is this statement true?

A. always
B. only for an object that floats
C. only for an object that sinks
D. never
Physics
2 answers:
Irina18 [472]3 years ago
7 0

Answer:

A. Always true

Explanation:

This is because, the buoyancy force is always present whenever and object is placed in a fluid. The magnitude of this  buoyancy force is always equal to the weight of the fluid    displaced by the object according to Archimedes' principle. This principle is true irrespective of whether the object floats or not. When any object is inserted in a fluid, the buoyancy force is always present irrespective of whether it floats or not.  

sp2606 [1]3 years ago
3 0

Answer:

The correct option is;

A. always

Explanation:

Archimedes' principle states that when an object is immersed in a fluid, and it is either partially or wholly submerged, the upward force acting on the object, that is the buoyancy force, is equal to the weight of the fluid displaced by the object.

That is the object immersed in the fluid is observed to have an apparent reduction in weight that is equal to the weight of the volume of the fluid displaced by the  immersed  object.

Therefore, the above principle always occurs.

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An airplane pilot wishes to fly directly westward. According to the weather bureau, a wind of 75.0km/hour is blowing southward.
qaws [65]

Answer:

a)  correct answer is C , b) 14º  from the west to the north, c)   v_{1g} = 300.79 km / h

Explanation:

This is a relative speed exercise using the addition of speeds.

1) when it is not specified regarding what is being measured, the medicine is carried out with respect to the Z Earth, therefore the correct answer is C

2 and 3) In this case we must compose the speed using the Pythagorean Theorem.

     v_{1a}² = v_{1g}² + v_{ag}²

where v_{1a} is the speed of the airplane with respect to the air, v_{1g} airplane speed with respect to the Earth, v_{ag} air speed with respect to the Earth

in this case let's clear the speed of the airplane with respect to the Earth

  v_{1g} = √(v_{1a}² - v_{ag}²)

 v_{1g} = √ (310² - 75²)

 v_{1g} = 300.79 km / h

we find the direction of the airplane using trigonometry

   sin θ = v_{ag} / v_{1a}

   θ = sin⁻¹ (v_{ag} /v_{1a})

   θ = sin⁻¹ (75/310)

   θ= 14º

the pilot must direct the aircraft at an angle of 14º from the west to the north

7 0
3 years ago
A 1.5 kg spherical ball is has a radius of 50 cm is rotating with angular velocity of 12 revolutions per minute. Determine the r
kykrilka [37]

Answer:

K.E = 0.0075 J

Explanation:

Given data:

Mass of the ball = 1.5 kg

radius, r = 50 cm = 0.5 m

Angular speed, ω = 12 rev/min = (12/60) rev/sec = 0.2 rev/sec

Now,

the kinetic energy is given as:

K.E = K.E=\frac{1}{2}I\omega^2

where,

I is the moment of inertia = mr²

on substituting the values, we get

K.E=\frac{1}{2}\times1.5\times0.5^2\times0.2^2

or

K.E = 0.0075 J

3 0
3 years ago
At a point 1.2 m out from the hinge, 14.0 N force is exerted at an angle of 27 degrees to the moment arm in a plane which is per
geniusboy [140]

Answer:

\tau = 7.63 Nm

Explanation:

As we know that moment of force is given as

\tau = \vec r \times \vec F

now we have

\vec r = 1.2 m

\vec F = 14 N

now from above formula we have

\tau = r F sin\theta

here we know that

\theta = 27 degree

so we have

\tau = (1.2)(14) sin27

\tau = 7.63 Nm

3 0
3 years ago
The top pair of pliers failed to loosen a stubborn bolt, but the bottom pair successfully removed it.
Lesechka [4]

The top pair of pliers failed to loosen a stubborn bolt, but the bottom pair successfully removed it. Because the contact between the bolt and the   pliers working surface is less.

<h3>What is mechanical advantage ?</h3>

Mechanical advantage is a measure of the ratio of output force to input force in a system, it is used to obtained efficiency of the given mechanical machine.

The efficiency to open the stubborn bolt depends upon the contact between the working surface of the pliers and the bolt.

The contact between the bolt and the top pair of pliers working surface is less. Its mechanical advantage is less.

Hence, the top pair of pliers failed to loosen a stubborn bolt, but the bottom pair successfully removed it.

To learn more about the mechanical advantage, refer to the link;

brainly.com/question/7638820

#SPJ1

3 0
2 years ago
A wire along the z axis carries a current of 4.9 A in the z direction Find the magnitude and direction of the force exerted on a
AURORKA [14]

Answer:

<h2>0.069 N, in the X direction</h2>

Explanation:

According to Flemming's left hand rule, it sates that if the first three fingers of the left hand are held mutually at right angles to one another, the fore finger will point in the direction of magnetic field, the middle finger will point in direction of current, while the thumb will point to the direction of force.

Mathematically the law is stated as

F= BIL

given data

Magnetic field B=  0.43T

Current I= 4.9 A

length of conductor L= 3.3cm to meter , 3.3/100=  0.033 m

Applying the formula the force is calculated as

F= 0.43*4.9* 0.033= 0.069 N

According to Flemming's rule the direction of all parameters are mutually perpendicular to one another, then the Force is in the X direction

5 0
3 years ago
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