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Basile [38]
3 years ago
12

An object is placed in a fluid and then released. Assume that the object either floats to the surface (settling so that the obje

ct is partly above and partly below the fluid surface) or sinks to the bottom. (Note that, for Parts A through D, you should assume that the object has settled in equilibrium.)
A.Consider the following statement: The magnitude of the buoyancy force is equal to the weight of fluid displaced by the object.
Under what circumstances is this statement true?

A. always
B. only for an object that floats
C. only for an object that sinks
D. never
Physics
2 answers:
Irina18 [472]3 years ago
7 0

Answer:

A. Always true

Explanation:

This is because, the buoyancy force is always present whenever and object is placed in a fluid. The magnitude of this  buoyancy force is always equal to the weight of the fluid    displaced by the object according to Archimedes' principle. This principle is true irrespective of whether the object floats or not. When any object is inserted in a fluid, the buoyancy force is always present irrespective of whether it floats or not.  

sp2606 [1]3 years ago
3 0

Answer:

The correct option is;

A. always

Explanation:

Archimedes' principle states that when an object is immersed in a fluid, and it is either partially or wholly submerged, the upward force acting on the object, that is the buoyancy force, is equal to the weight of the fluid displaced by the object.

That is the object immersed in the fluid is observed to have an apparent reduction in weight that is equal to the weight of the volume of the fluid displaced by the  immersed  object.

Therefore, the above principle always occurs.

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Answer:

f=81.96 \ Hz

Explanation:

Givens

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Where v is the speed of the wave in the string and \lambda is its wave length.

The wave length is defined as \lambda = 2L = 2(0.95m)=1.9m

Now, to find the speed, we need the tension of the wire and its linear mass density

v=\sqrt{\frac{T}{\mu} }

Where \mu=\frac{0.005kg}{0.95m}= 5.26 \times 10^{-3} and the tension is defined as T=m_{sculpture} g=13kg(9.81 m/s^{2} )=127.53N

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v=\sqrt{\frac{127.53N}{5.26 \times 10^{-3} } }=155.71 m/s

Then, we replace the speed and the wave length in the first equation

f=\frac{v}{\lambda}\\f=\frac{155.71 m/s}{1.9m}\\ f=81.96Hz

Therefore, the frequency is f=81.96 \ Hz

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