The weight required to stretch the spring 12.5 cm is 7.5 N (Option A)
<h3>Data obtained from the question</h3>
- Initial weight (W₁) = 3 N
- Initial Length (L₁) = 5 cm
- New length (L₂) = 12.5 cm
- New Weight (W₂) =?
<h3>How to determine the new weight </h3>
The new weight required to stretch the spring can be obtained as follow:
W₁ / L₁ = W₂ / L₂
3 / 5 = W₂ / 12.5
Cross multiply
W₂ × 5 = 3 × 12.5
Divide both sides by 5
W₂ = (3 × 12.5) / 5
W₂ = 7.5 N
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Answer:
C. 1.4 m/s
Explanation:
Energy is conserved:
Initial energy = final energy
At P, the pendulum has only gravitational potential energy.
At Q, the pendulum has only kinetic energy.
PE = KE
mgh = ½mv²
v = √(2gh)
Given h = 0.1 m:
v = √(2 × 9.8 m/s² × 0.1 m)
v = 1.4 m/s
Answer:
A greater period.
Explanation:
The period of a simple pendulum is represented by the following formula:
Where:
- Length of the pendulum
- Gravity constant
Given that gravity constant in the Moon is less than on Earth, period shall be greater.
