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2 years ago

a recipe requires 1/2 cup of milk and 1/3 cup of water. How much more milk is required for tge recipe than water?

Mathematics

1 answer:

ycow [4]2 years ago

7 0

Answer:

1/6 cup of milk

Step-by-step explanation:

1/2 (amount of milk)- 1/3 (amount of water)

1/2 = 3/6

1/3 = 2/6

3/6 - 2/6 = 1/6

Hope this helped <3

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Someone please help with this means a lot! 8th grade algebra. thanks <3

-BARSIC- [3]

Answer:

Step-by-step explanation:

4 0

3 years ago

The volume of a cube is 125 cm^3. The area of a square is 64 cm^2. How does the lenghth of one edge of the cube compare to the l

anzhelika [568]

Answer:

One edge of the cube is 5 cm, one edge of the square is 8 cm, so the edge of the cube is 3 cm shorter than the edge of the square.

Step-by-step explanation:

<h3 /><h3>The volume of the cube is found by the formula </h3><h2>V = s³, </h2><h3>where s is the side length (called the edge in this problem)</h3><h3>Since V = 125 cm³, we can take the cube root of 125 to find the edge length.</h3><h3>The cube root of 125 is 5, ( 5³ = 125)</h3><h3>So the edge of the cube is 5 cm</h3><h3 /><h3>The are of a square is found by the formula </h3><h2>A = s² , </h2><h3>where s is the side length (called the edge in this problem) </h3><h3>Since A = 64 cm², we can take the square root of 64 to find the edge length.</h3><h3>The square root of 64 is 8 (8² = 84)</h3><h3>So the edge of the square is 8cm</h3><h3 /><h3>Comparing the two edges tells us that the edge of the cube is 3cm shorter than the edge of the square.</h3>

8 0

2 years ago

Solve sin 0 + 1 = cos20 on the interval 0 ≤ 0 < 2pi. Show work please!

yan [13]

Answer:

$\theta=\frac{\pi}{2},\frac{3\pi}{2}\frac{2\pi}{3}\frac{4\pi}{3}$

Step-by-step explanation:

You need 2 things in order to solve this equation: a trig identity sheet and a unit circle.

You will find when you look on your trig identity sheet that

$cos(2\theta)=1-2sin^2(\theta)$

so we will make that replacement, getting everything in terms of sin:

$sin(\theta)+1=1-2sin^2(\theta)$

Now we will get everything on one side of the equals sign, set it equal to 0, and solve it:

$2sin^2(\theta)+sin(\theta)=0$

We can factor out the sin(theta), since it's common in both terms:

$sin(\theta)(2sin(\theta)+1)=0$

Because of the Zero Product Property, either

$sin(\theta)=0$ or

$2sin(\theta)+1=0$

Look at the unit circle and find which values of theta have a sin ratio of 0 in the interval from 0 to 2pi. They are:

$\theta=\frac{\pi}{2},\frac{3\pi}{2}$

The next equation needs to first be solved for sin(theta):

$2sin(\theta)+1=0$ so

$2sin(\theta)=-1$ and

$sin(\theta)=-\frac{1}{2}$

Go back to your unit circle and find the values of theta where the sin is -1/2 in the interval. They are:

$\theta=\frac{2\pi}{3},\frac{4\pi}{3}$

7 0

2 years ago

Suppose a triangle has 2 sides of length 3 and 4 and that the angle between these two sides is 60 degrees. what is the length of

shusha [124]

Answer:

$\boxed{b.\:\:\:\sqrt{13}}$

Step-by-step explanation:

Let the third side of the triangle be $h\: units$ .

We can apply the cosine rule to find $h$ .

$h^2=3^2+4^2-2(3)(4)\cos(60\degree)$

We evaluate to obtain;

$\Rightarrow h^2=9+16-24(\frac{1}{2})$

$\Rightarrow h^2=25-12$

$\Rightarrow h^2=13$

We take the positive square root of both sides to obtain;

$\Rightarrow h=\sqrt{13}$

The correct answer is B.

8 0

2 years ago

data set A is {30, 45, 32, 50, 33, 40, 44, 32}. Data set B is {28, 43, 30, 48, 35, 42, 46, 34}. which statement best compares th

3241004551 [841]

Answer:

the mean in set B is equal to the mean in set A (option C)

Question:

The question is incomplete as the answer choices were not given.Let's consider the following question:

Data set A is {30, 45, 32, 50, 33, 40, 44, 32}. Data set B is {28, 43, 30, 48, 35, 42, 46, 34}. which statement best compares the two data sets?

a) median for set A is equal to the median for set B

b) Range for set A is greater than range for set B

c) The mean in set B is equal to the mean in set A

Step by step explanation:

We can describe a data set using four ways:

Center, spread, shape and unusual features.

Let's consider the center and spread.

Center: This is the median of the distribution.

Spread: This is the variation of the data set. If the range is wide, the spread is larger and If the range is small, the spread is smaller.

Rearranging the data set:

A = {30, 32, 32, 33, 40, 44, 45, 50}

B = {28, 30, 34, 35, 42, 43, 46, 48}

From the data:

The median for set A = (33+40)/2 = 73/2= 36.5

The median for set B = (35+42)/2 = 77/2= 38.5

Range = highest value - lowest value

The data ranges from 30 to 50 (range = 20) for A

The data ranges from 28 to 48 (range = 20) for B

Mean for set A = (30+32+32+33+40+4445+50)/8 = 306/8 = 38.25

Mean for set B = (28+30+34+35+42+43+46+48)/8= 306/8 = 38.25

In both data set the mean is equal to 38.25.

Therefore the statement that best compares the two data sets is the mean in set B is equal to the mean in set A (C)

8 0

3 years ago

a recipe requires 1/2 cup of milk and 1/3 cup of water. How much more milk is required for tge recipe than water? ​

a recipe requires 1/2 cup of milk and 1/3 cup of water. How much more milk is required for tge recipe than water?