I have found the area but I'm not sure how to find the perimeter.
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check the picture below.
bearing in mind that there are 60 minutes in 1 degree, then 16°18' will be 16.3° and likewise 48°51' will be 48.85° if we convert those to degrees only.
Check the picture below
now, <span>26°35' is just 26bdegrees and 35 minutes
your calculator most likely will have a button [ </span><span>° ' " ] to enter degrees and minutes and seconds
there are 60 minutes in 1 degree and 60 seconds in 1 minute
so.. you could also just convert the 35' to 35/60 degrees
so </span>![\bf 26^o35'\implies 26+\frac{35}{60}\implies \cfrac{1595}{60}\iff \cfrac{319}{12} \\\\\\ tan(26^o35')\iff tan\left[ \left( \cfrac{391}{12} \right)^o \right]](https://tex.z-dn.net/?f=%5Cbf%2026%5Eo35%27%5Cimplies%2026%2B%5Cfrac%7B35%7D%7B60%7D%5Cimplies%20%5Ccfrac%7B1595%7D%7B60%7D%5Ciff%20%5Ccfrac%7B319%7D%7B12%7D%0A%5C%5C%5C%5C%5C%5C%0Atan%2826%5Eo35%27%29%5Ciff%20tan%5Cleft%5B%20%5Cleft%28%20%5Ccfrac%7B391%7D%7B12%7D%20%5Cright%29%5Eo%20%5Cright%5D)
now, the angle is in degrees, thus, make sure your calculator is in Degree mode
now, <span>26°35' is just 26bdegrees and 35 minutes
your calculator most likely will have a button [ </span><span>° ' " ] to enter degrees and minutes and seconds
there are 60 minutes in 1 degree and 60 seconds in 1 minute
so.. you could also just convert the 35' to 35/60 degrees
so </span>
now, the angle is in degrees, thus, make sure your calculator is in Degree mode