1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Bad White [126]
3 years ago
15

An object has a velocity of 10m/s south. in what direction is its momentum

Physics
1 answer:
Tanya [424]3 years ago
7 0
The direction is from the west
You might be interested in
Which two factors determine the force of gravity between two objects?
Mila [183]
Distance and inertia
5 0
3 years ago
Which illustration represents high accuracy but low precision?<br><br><br> plz help
Mashutka [201]

Answer:

A

Explanation:

8 0
4 years ago
Read 2 more answers
A 24-cm-diameter vertical cylinder is sealed at the top by a frictionless 15 kg piston. The piston is 90 cm above the bottom whe
abruzzese [7]

Answer:

(A) P_i=3249.41\ Pa

(B) V_f=0.3358\ m

Explanation:

Given:

  • diameter of the cylinder, d= 0.24\ m
  • mass of piston sealing on the top, m_p=15\ kg
  • initial temperature of the piston, T_i=315+273= 588\ K
  • initial height of piston, h_i=0.9\ m
  • atmospheric pressure on the piston, p_a=1 atm=101325\ Pa

(A)

<u>Initial pressure of gas is the pressure balanced by the weight of piston:</u>

P_i=\frac{m_p.g}{\pi.d^2\div 4}

P_i=\frac{15\times 9.8}{\pi\times (0.24^2\div 4)}

P_i=3249.41\ Pa

<em>Which is gauge pressure because it is measured with respect to the atmospheric pressure.</em>

(B)

Given:

  • Final temperature, T_f=18+273=291\ K

<u>Now, volume of air initially in the cylinder:</u>

V_i=\pi.d.h_i

V_i=\pi\times 0.24\times 0.9

V_i=0.6786\ m^3

Using gas law:

\frac{P_i V_i}{T_i}= \frac{P_f V_f}{T_f} ........................................(1)

<em>∵In every condition of equilibrium the gas pressure will be balanced by the weight of the piston so it is an </em><em>isobaric transition</em><em>.</em>

∴P_i=P_f

<u>Hence eq. (1) is reduced to:</u>

\frac{V_i}{T_i}= \frac{V_f}{T_f}

putting respective values:

\frac{0.6786}{588}= \frac{V_f}{291}

V_f=0.3358\ m

6 0
4 years ago
A ball is thrown horizontally from the top of
kolezko [41]

Answer:

whattt

Explanation:

<h2><em>sorry dear I did not understand</em></h2>
5 0
3 years ago
You measure the velocity of a drag racer that accelerates with constant acceleration. You want to plot the data and determine th
Ivenika [448]

Answer:

a) Linear equation

Explanation:

Definition of acceleration

a=\frac{dv}{dt}\\

if a=constant and we integrate the last equation

v(t)=v_{o}+a*t

So the relation between the time and the velocity is linear. If we plot the velocity in function of time, the plot is a line, and the acceleration is the slope of this line.

8 0
3 years ago
Other questions:
  • If the only forces acting on a 2.0kg mass are F1 = (3i-8j)N and F2 = (5i+3j)N, what is the magnitude of the acceleration of the
    5·1 answer
  • an n-type semiconductor is known to have an electron concentration of 5.63 x 1019 m-3. if the electron drift velocity is 113 m/s
    5·1 answer
  • What would stars be like if hydrogen had the smallest mass per nuclear particle? What would stars be like if hydrogen had the sm
    6·1 answer
  • This surface feature of the moon is common it was once thought to be ancient seas
    15·1 answer
  • Two particles execute simple harmonic motion of the same amplitude and frequency along close parallel lines. They pass each othe
    5·1 answer
  • Which part of the ear receives the signal from the eardrum?​
    9·1 answer
  • HELP!!!! WILL MARK BRAINLIEST!!!! IF YOU LEAVE AN ANSWER EXPLAIN! THANKS
    5·1 answer
  • Pllssss answer thiss ...<br> its about the reading of VOLTMETER AND AMMETER
    6·1 answer
  • When 24.0 V is applied to a
    11·1 answer
  • A group of physicists perform an experiment. The measurements that they took were carefully made but they failed to obtain the c
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!