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svp [43]
2 years ago
5

What parameters affects the inductance of a coil​

Physics
1 answer:
Kazeer [188]2 years ago
4 0

Answer:

Number of Wire Turns in the Coil.

Explanation:

The greater the number of turns of wire in the coil, the greater the inductance. Fewer turns of wire in the coil results in lesser inductance. More coils of wires indicate a greater amount of magnetic field force for a given amount of coil current.

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Suppose you are planning a trip in which a spacecraft is to travel at a constant velocity for exactly six months, as measured by
mylen [45]

Answer:

<em>I must travel with a speed of 2.97 x 10^8 m/s</em>

Explanation:

Sine the spacecraft flies at the same speed in the to and fro distance of the journey, then the time taken will be 6 months plus 6 months

Time that elapses on the spacecraft = 1 year

On earth the people have advanced 120 yrs

According to relativity, the time contraction on the spacecraft is gotten from

t = t_{0} /\sqrt{1 - \beta ^{2} }

where

t is the time that elapses on the spacecraft = 120 years

t_{0} = time here on Earth = 1 year

\beta is the ratio v/c

where

v is the speed of the spacecraft = ?

c is the speed of light = 3 x 10^8 m/s

substituting values, we have

120 = 1/\sqrt{1 - \beta ^{2} }

squaring both sides of the equation, we have

14400 = 1/(1 - \beta ^{2} )

14400 - 14400\beta ^{2} = 1

14400 - 1 = 14400\beta ^{2}

14399 = 14400\beta ^{2}

\beta ^{2} =  14399/14400 = 0.99

\beta = \sqrt{0.99} = 0.99

substitute β = v/c

v/c = 0.99

but c = 3 x 10^8 m/s

v = 0.99c = 0.99 x 3 x 10^8 = <em>2.97 x 10^8 m/s</em>

6 0
3 years ago
What is the difference between an observation and an inference?
Vinvika [58]

Explanation:

observation is something what you could observe from your organs like eyes ears etc and also it is what you observed during an event for an experiment but inference is what you decide to do after observation or an event.

the act of inferring (to derive by reasoning). Observation = an act or instance of noticing or perceiving.

Thank u!

5 0
3 years ago
(d) If η = 40% and TH = 427°C, what is TC, in °C?
Brrunno [24]

Answer:

T_C=256.2^{\circ}C

Explanation:

Given that,

Efficiency of heat engine, \eta=40\%=0.4

Temperature of hot source, T_H=427^{\circ}C

We need to find the temperature of cold sink i.e. T_C. The efficiency of heat engine is given by :

\eta=1-\dfrac{T_C}{T_H}

T_C=(1-\eta)T_H

T_C=(1-0.4)\times 427

T_C=256.2^{\circ}C

So, the temperature of the cold sink is 256.2°C. Hence, this is the required solution.

3 0
3 years ago
A circuit has a resistance of 10 Ω and current of 5 A. What is the voltage?<br><br>​
raketka [301]

Answer: 50 V

Explanation:

V=IR\\V=(5)(10)\\V=50

6 0
3 years ago
A 1.70 m tall woman stands 5.00 m in front of a camera with a 50.00 cm focal
slamgirl [31]

Answer:

18.89cm

Explanation:

As we know that the person is standing 5m in front of the camera

d_0=5m=500cm

The focal length of the lens =50cm

f=50 cm

By Lens formula we have:

\dfrac{1}{f} = \dfrac{1}{d_i} + \dfrac{1}{d_o}\\\dfrac{1}{50} = \dfrac{1}{d_i} + \dfrac{1}{500}\\\dfrac{1}{d_i} =\dfrac{1}{50}-\dfrac{1}{500}\\\dfrac{1}{d_i}=0.018\\d_i=55.56cm

By the formula of magnification

\dfrac{h_i}{h_o} = \dfrac{55.56}{500}\\\\h_i = \dfrac{55.56}{500} \times h_o\\\\ h_o=1.70m=170cm\\\\Therefore: h_i=\dfrac{55.56}{500} \times$ 170 cm\\\\h_i =18.89 cm

The height of the image formed is 18.89cm.

5 0
3 years ago
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