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marysya [2.9K]
3 years ago
9

A Tesla Roadster car accelerates from rest at a rate of 7.1m/s for a time of 3.9s

Physics
1 answer:
liberstina [14]3 years ago
5 0

The distance covered is 54.0 m

Explanation:

Since the motion of the car is a uniformly accelerated motion, we can use the following suvat equation:

s=ut+\frac{1}{2}at^2

where

u is the initial velocity

t is the time

a is the acceleration

s is the distance covered

For the car in this problem, we have

u = 0 (it starts from rest)

a=7.1 m/s^2 is the acceleration

t = 3.9 s is the time

Substituting, we find s:

s=0+\frac{1}{2}(7.1)(3.9)^2=54.0 m

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

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Answer:

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The insert in the tube creates a closed pipe with one end open and the other closed. For a closed pipe, the difference between successive resonances is a half wavelength \frac{\lambda}{2}.

Hence, we have

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A girl swings on a playground swing in such a way that at her highest point she is 4.1 m from the ground, while at her lowest po
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Answer:

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Explanation:

height at highest point (h2) = 4.1 m

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from conservation of energy, the total energy at the lowest point will be the same as the total energy at the highest point. therefore

mgh1 + 0.5mV1^{2} = mgh2 + 0.5mV2^{2}

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  • therefore the equation becomes mgh1 + 0.5mV1^{2} = mgh2

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V1 = \sqrt{\frac{32.34}{0.5}}

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