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azamat
3 years ago
6

An optical disk drive in your computer can spin a disk up to 10,000 rpm (about 1045 rad/s). If a particular disk is spun at 646.

1 rad/s while it is being read, and then is allowed to come to rest over 0.569 seconds, what is the magnitude of the average angular acceleration of the disk?
Physics
1 answer:
lesya692 [45]3 years ago
3 0

Answer:

Angular acceleration will be 1135.5rad/sec^2

Explanation:

We have given initial angular speed of a particular disk \omega _i=646.1rad/sec

And it finally comes to rest so final angular speed \omega _f=0rad/sec

Time is given as t = 0.569 sec

From third equation of motion we know that

\omega _f=\omega _i+\alpha t

So angular acceleration \alpha =\frac{\omega _f-\omega _i}{t}=\frac{0-646.1}{0.569}=1135.5rad/sec^2

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Answer:

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Explanation:

3 0
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A graph that shows how position depends on time is a?
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A graph that shows how position is depending on time is known as a Position Time Graph.

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8 0
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A technique in which the muscles are stretched by an outside force is called _____.
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3 years ago
A girl throws a ball of mass 0.8 kg against a wall. The ball strikes the wall horizontally with a speed of 11 m/s, and it bounce
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Answer:

F = 352 N

Explanation:

we know that:

F*t = ΔP

so:

F*t = MV_f-MV_i

where F is the force excerted by the wall, t is the time, M the mass of the ball, V_f the final velocity of the ball and V_i the initial velocity.

Replacing values, we get:

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3 0
3 years ago
A 20 kg shopping cart moving at a velocity of 0.5 m/s collides with a store wall and
MAXImum [283]

Answer:

<h2>10 kg.m/s</h2>

Explanation:

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From the question we have

momentum = 20 × 0.5

We have the final answer as

<h3>10 kg.m/s</h3>

Hope this helps you

7 0
2 years ago
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