If the volume is held constant, what happens to the pressure of a gas as temperature is decreased? Explain.
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The ball takes 0.2 sec to travel the height of the window, which is 2 m.
Then the speed of the ball at that time was
We know that:
Where is the initial velocity.
So:
Then we have the equation for the position as a function of time.
Where
= initial position
r = position as a function of time
= initial velocity
g = acceleration of gravity
t = time.
If the ball is thrown from the ground then:
= 0 m
We want to find now the distance between the window and the ground.
When the ball reaches the bottom of the window t = 1.8s
So:
m
The window is 37,404 m high
Finally, to know how high the ball rises we must know at what moment the vertical velocity of the ball is zero.
Now we replace t in the position equation
The ball reaches up to 44.70 m in height.
Answer:
The answer is below
Explanation:
Charlee's law states that the volume of a gas is directly proportion to the temperature of the gas at constant pressure. That is:
V = kT, where V = volume and T = temperature, k = constant. Therefore:
V / T = k
Given that:
The new volume is 3.41 m³. That is it expands by 0.41 m³