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bekas [8.4K]
3 years ago
13

Galaxy A is located 200 million light-years from Earth, while galaxy B is located 600 million light-years from Earth. According

to the Hubble law, how does the motion of the two galaxies compare?
A. Galaxies A and B are moving away from Earth at the same rate.
B. Galaxy A is moving away from Earth three times as fast as galaxy B.
C. Galaxy B is moving away from Earth three times as fast as galaxy A.
Physics
1 answer:
Ray Of Light [21]3 years ago
8 0

Answer:

C

Explanation:

I think c is correct due to reason given by you

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If Star A is twice as far as Star B, and they are identical in all other ways, then the
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A student wants to determine the impulse delivered to the lab cart when it runs into the wall. The student measures the mass of
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Impulse = Force * times and also Impulse = change in momentum.

Given that the mass does not change, change if momentum = mass * (final velocity -  initial velocity)

Given that you know mass and initial velocity (which is the velicity before the cart hits the wall) you need the final velocity (which is the velocity after the cart hits the wall).

Answer: the velocity of the cart after it hits the wall.
6 0
3 years ago
. A 40.0-kg child standing on a frozen pond throws a 0.500-kg stone to the east with a speed of 5.00 m/s. Neglecting friction be
tamaranim1 [39]

Answer:

Explanation:

A 40kg child throw stone of 0.5kg

At a direction of 5m/s

Recoil can be calculated using recoil of a gun formula

m_1•v_1 + m_2•v_2

m_1•v_1 = -m_2•v_2

The negative sign show that the momentum of the boy is directed oppositely to that of the stone

m_1 Is mass of boy

v_1 is the recoil velocity of the boy

m_2 is mass of stone

v_2 is the velocity of stone

Then,

m_1•v_1 = -m_2•v_2

40•v_1 = -0.5 × 5

40•v_1 = -2.5

v_1 = -2.5 / 40

v_1 = -0.0625 m/s

The recoil velocity of the boy is 0.0625 m/s

6 0
3 years ago
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