Answer
given,
mass of block, m = 2 Kg
spring constant, k = 315 N/m
speed of the block, v = 12 m/s
a) Amplitude of the motion
A = 0.956 m
b) maximum acceleration of the block
c) maximum Force
Galaxy A is located 200 million light-years from Earth, while galaxy B is located 600 million light-years from Earth. According
1 answer:
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Answer:
(a) 333.77 J
(b) 237.85 J
(c) 4763.77 J
(d) 4667.85 J
Explanation:
Temperature of source, TH = 314 K
Temperature of A, Tc = 292 K
Temperature of B, Tc' = 298 K
heat taken out, Qc = 4430 J
Let the heat deposited outside is QH and QH' by A and B respectively.
Now
(a) Work done for A
W = QH - QC = 4763.77 - 4430 = 333.77 J
(b) Work done for B
W' = QH' - Qc = 4667.85 - 4430 = 237.85 J
(c) QH = 4763.77 J
(d) QH' = 4667.85 J
The question is: A tuning fork vibrates at 140 [Hz] and the wave emitted by it propagates with a speed of 340 m / s. Considering the above, it can be correctly stated that the wavelength of the wave emitted by the tuning fork is
Answer: Wavelength of the wave emitted by the tuning fork is 2.43 m.
Explanation:
Given: Frequency = 140 Hz
Speed = 340 m/s
wavelength = ?
Formula used to calculate the wavelength is as follows.
where,
= wavelength
v = speed
f = frequency
Substitute the values into above formula.
Thus, we can conclude that wavelength of the wave emitted by the tuning fork is 2.43 m.