First, we will get the distance traveled before the driver applied the brakes.
distance = velocity * time
distance = 25*0.34 = 8.5 m
Now, we will calculated the distance that the car traveled after the driver applied the brakes. To do this, we will use the equation of motion:
<span>vf^2 = vi^2 + 2*a*d where:
</span>vf = zero, vi = 25 m/s and a = -7 m/s^2
Note: The negative sign is only to show deceleration
d = <span> 1/2*(625) /(7) = 44.6428 m
The total stopping distance =</span> 8.5 + 44.6428 = 53.1428 m
Answer:
0.46km
Explanation:
45963cm/100cm=459.63m/1000m=0.45963 or 0.46km
Answer: 52.
Explanation: Critical Thinking When a ball is thrown vertically up, it keeps going up until it hits a certain position, and then falls down. At the maximum point, the velocity is instantaneously zero.
I may or may not be a nerd lol.
Hope This Helps!!! : )
To solve this problem, we use the equation:
<span>d = (v^2 - v0^2) /
2a</span>
where,
d = distance of collapse
v0 = initial velocity = 101 km / h = 28.06 m / s
v = final velocity = 0
a = acceleration = - 300 m / s^2
d = (-28.06 m / s)^2 / (2 * - 300 m / s^2)
<span>d = 1.31 m</span>