Air and water have a good day
Acceleration = v-u/t
= (45-30)/15
= 1 km/h
Distance = ut + 1/2 at^2
s = [30 x 15] + 1/2 x 1 x 15^2
= 562.5 km
Hope this helps
Answer:
![8.64283\times 10^{-14}\ N](https://tex.z-dn.net/?f=8.64283%5Ctimes%2010%5E%7B-14%7D%5C%20N)
Explanation:
q = Charge of proton = ![1.6\times 10^{-19}\ C](https://tex.z-dn.net/?f=1.6%5Ctimes%2010%5E%7B-19%7D%5C%20C)
v = Velocity of proton = ![0.267\times c](https://tex.z-dn.net/?f=0.267%5Ctimes%20c)
c = Speed of light = ![3\times 10^8\ m/s](https://tex.z-dn.net/?f=3%5Ctimes%2010%5E8%5C%20m%2Fs)
B = Magnetic field = 0.00687 T
= Angle = ![101^{\circ}](https://tex.z-dn.net/?f=101%5E%7B%5Ccirc%7D)
Magnetic force is given by
![F=qvBsin\theta\\\Rightarrow F=1.6\times 10^{-19}\times (0.267\times 3\times 10^8)\times 0.00687\times sin101\\\Rightarrow F=8.64283\times 10^{-14}\ N](https://tex.z-dn.net/?f=F%3DqvBsin%5Ctheta%5C%5C%5CRightarrow%20F%3D1.6%5Ctimes%2010%5E%7B-19%7D%5Ctimes%20%280.267%5Ctimes%203%5Ctimes%2010%5E8%29%5Ctimes%200.00687%5Ctimes%20sin101%5C%5C%5CRightarrow%20F%3D8.64283%5Ctimes%2010%5E%7B-14%7D%5C%20N)
The magnetic force acting on the proton is ![8.64283\times 10^{-14}\ N](https://tex.z-dn.net/?f=8.64283%5Ctimes%2010%5E%7B-14%7D%5C%20N)
Answer:
A protractor to measure the angle of the inclined plane with the horizontal
Explanation:
The student needs to lift the free end of the adjustable inclined plane until the object barely starts sliding, and measure the angle at which such happens. At that point, the force of friction equals the component of the weight in the direction of the incline. That is:
![f=\mu\,* N = \mu * m g\, cos(\theta)](https://tex.z-dn.net/?f=f%3D%5Cmu%5C%2C%2A%20N%20%3D%20%5Cmu%20%2A%20m%20g%5C%2C%20cos%28%5Ctheta%29)
and ![w_{//}= m\,g\,sin(\theta)](https://tex.z-dn.net/?f=w_%7B%2F%2F%7D%3D%20m%5C%2Cg%5C%2Csin%28%5Ctheta%29)
Then
![f = w_{//}\\\mu *\,m \,g\,cos(\theta) = m\,g\,sin(\theta)\\\mu = tan(\theta)](https://tex.z-dn.net/?f=f%20%3D%20w_%7B%2F%2F%7D%5C%5C%5Cmu%20%2A%5C%2Cm%20%5C%2Cg%5C%2Ccos%28%5Ctheta%29%20%3D%20m%5C%2Cg%5C%2Csin%28%5Ctheta%29%5C%5C%5Cmu%20%3D%20tan%28%5Ctheta%29)
and therefore, the coefficient of static friction is fully determined just by calculating the tangent of the angle that the incline forms with the horizontal.
Then the only extra instrument needed is a protractor to measure the angle.