Answer:
a)    x = v₀² sin 2θ / g
b)    t_total = 2 v₀ sin θ / g
c)    x = 16.7 m
Explanation:
This is a projectile launching exercise, let's use trigonometry to find the components of the initial velocity
         sin θ =  / vo
 / vo
         cos θ = v₀ₓ / vo
          v_{oy} = v_{o} sin θ
          v₀ₓ = v₀ cos θ
          v_{oy} = 13.5 sin 32 = 7.15 m / s
          v₀ₓ = 13.5 cos 32 = 11.45 m / s
a) In the x axis there is no acceleration so the velocity is constant
          v₀ₓ = x / t
           x = v₀ₓ t
the time the ball is in the air is twice the time to reach the maximum height, where the vertical speed is zero
           v_{y} = v_{oy} - gt
           0 = v₀ sin θ - gt
           t = v_{o} sin θ / g
          
we substitute
        x = v₀ cos θ (2 v_{o} sin θ / g)
        x = v₀² /g      2 cos θ sin θ
        x = v₀² sin 2θ / g
at the point where the receiver receives the ball is at the same height, so this coincides with the range of the projectile launch,
b) The acceleration to which the ball is subjected is equal in the rise and fall, therefore it takes the same time for both parties, let's find the rise time
at the highest point the vertical speed is zero
           v_{y} = v_{oy} - gt
           v_{y} = 0
            t = v_{oy} / g
            t = v₀ sin θ / g
as the time to get on and off is the same the total time or flight time is
            t_total = 2 t
            t_total = 2 v₀ sin θ / g
c) we calculate
           x = 13.5 2 sin (2 32) / 9.8
           x = 16.7 m
 
        
             
        
        
        
Answer:
98.13m
Explanation:
Complete question
Daniel is 50.0 meters away from a building. Tip of the building makes an angle of 63.0° with the horizontal. What is the height of the building
CHECK THE ATTACHMENT
From the figure, using trigonometry
Tan(θ ) = opposite/adjacent
Where Angle (θ )= 63°
Opposite= X = height of the building
Adjacent= 50 m
Then substitute the values we have
Tan(63)= X/50
1.9626= X/50
X= 1.9626 × 50
X= 98.13m
Hence, the height of the building is 98.13m
 
        
             
        
        
        
Answer:
240 V
Explanation:
number of turns in primary coil, Np = 10 
Number of loops in secondary coil, Ns = 20
Voltage in primary coil, Vp = 120 V 
Let the voltage in secondary coil is Vs. 
So, Vs / Vp = Ns / Np 
Vs / 120 = 20 / 10 
Vs / 120  = 2 
Vs = 240 V
Thus, the voltage in secondary coil is 240 Volt. 
 
        
             
        
        
        
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