Calculate the work done by a 4.2 N force pushing a 450. g sandwich across a table 0.8 m wide.
1 answer:
You might be interested in
Answer:
a) Δp = - 10113.2 Kg m / s, b) he rate of change is negative, c) F = 140.46N
Explanation:
a) For this part let's analyze a water particle, it has a velocity of 66 m / s and when it collides with the building its velocity changes to zero, so the change in moment is
Δp = mv_f - m v₀
Δp = -m v₀ (1)
the change of the moment in a second is
if 2429 gallons arrive in in minute (60s) in a second how many gallons arrive
c_agua = 2429/60
c_water = 40,483 gallon/ s
let's use the concept of density to find the mass
ρ = m / V
m = ρ V
let's reduce gallons to liters
c_water = 40,483 gal (3,785 l / 1 gal) = 153.23 l
m = 1 153.23
m 153.23 kg
we substitute in 1
Δp = - 153.23 66
Δp = - 10113.2 Kg m / s
b) From the previous result the rate of change is negative
c) Let's use the impulse ratio
I = f t = Δp
F t = Δp
F = Δp / t
F =
F = 140.46 N