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PtichkaEL [24]
3 years ago
15

Calculate the work done by a 4.2 N force pushing a 450. g sandwich across a table 0.8 m wide.

Physics
1 answer:
gladu [14]3 years ago
3 0

Answer:

3.36 Joules

Explanation:

Work done= Force × distance

F=4.2 N

distance= 0.8 m

work done= 4.2 × 0.8

work done= 3.36 Joules

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A child of mass 25 kg is skating fast, +10 m/s, and tries to get revenge by colliding with the 60 kg adult who is sitting still.
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Answer: -4.4 m/s

Explanation:

This problem can be solved by the Conservation of Momentum principle, which establishes that the initial momentum p_{o} must be equal to the final momentum p_{f}:

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Where:

p_{o}=m_{1}V_{o}+m_{2}U_{o} (2)

p_{f}=m_{1}V_{f}+m_{2}U_{f} (3)

m_{1}=25 kg is the mass of the child

V_{o}=10 m/s is the initial velocity of the child

m_{2}=60 kg is the mass of the adult

U_{o}=0 m/s is the initial velocity of the adult (it is sitting still)

V_{f} is the final velocity of the child

U_{f}=6 m/s is the final velocity of the adult

Substituting (2) and (3) in (1):

m_{1}V_{o}+m_{2}U_{o}=m_{1}V_{f}+m_{2}U_{f} (4)

Isolating V_{f}:

V_{f}=\frac{m_{1}V_{o}-m_{2}U_{f}}{m_{1}} (5)

V_{f}=\frac{(25 kg)(10 m/s)-(60 kg)(6 m/s)}{25 kg} (6)

Finally:

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What is the direction of force of friction acting ona moving objec
PIT_PIT [208]
The direction of the friction force is the same than the movement, but its sense is the opposite.
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