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Yuliya22 [10]
3 years ago
9

The sensor in the torso of a crash test dummy records the magnitude znd direction of the net force acting on the dummy.If the du

mmy is thrown forward with a force of 130.0N while simultandously being hit from the side wigh a force of 4500.0N,what force will the sensor report
Physics
1 answer:
muminat3 years ago
7 0

Here in the given situation two forces are acting on the dummy from two perpendicular directions

Since force is a vector quantity so we need to add two or more forces by vector addition method

Now here we know that two forces are perpendicular to each other

So we will use Pythagoras theorem

F_{net} = \sqrt{F_1^2 + F_2^2}

given that

F_1 = 130.0 N

F_2 = 4500.0 N

now plug in all in the above equation

F_{net} = \sqrt{130^2 + 4500^2}

F_{net} = 4501.9 N

So the sensor will report net force as 4501.9 N

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