3 years ago

Can someone help me with this question?

Mathematics

1 answer:

nevsk [136]3 years ago

7 0

Step-by-step explanation:

1. Vertical

2. Alternate

3. congruent

4. AAS or SAA

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One-fourth of the sum of 6 and 2 times c exceeds 3.

Sergeeva-Olga [200]

1/4(6 + 2c) > 3
0.25 (6+ 2c) > 3
1.5 + 0.5c > 3
0.5c > 1.5
c > 3

Or multiply both sides by 4 to get rid of the 1/4,
6 + 2c > 12
2c > 6
c >3

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2 years ago

Every day, Jason runs for 36 minutes and lifts weights for 44 minutes. How many minutes will Jason spend working out in 8 days?

Lisa [10]

36 x 8 = 288
44 x 8 = 352
288 + 352 = 640
So 640 minutes in 8 days.

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2 years ago

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An angle of 34°. If the arc is 162 feet tall, how far away is the bus? Round to the nearest tenth.

marta [7]

Answer:

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2 years ago

M(3,6) is the midpoint of Rs The coordinates of S are (5,9). What are the coordinates of R? O 17, 12) O (4, 7.5) O (6, 12) O (1,

miss Akunina [59]

Answer:

Step-by-step explanation:

(x+5)/2 = 3

x + 5 = 6

x = 1

(y+9)/2=6

y+9= 12

y = 3

(1, 3)

answer is option 4

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2 years ago

In ΔABC, if m ∠A = m∠C, m∠B = ß (where ß is an acute angle), and BC = x, which expression gives the length of b, the side opposi

chubhunter [2.5K]

Answer:

The length of b is $\sqrt{2x^2(1-cos\beta)}$ .

Step by step explanation:

Given information: In ΔABC, ∠A =∠C, ∠B = ß (where ß is an acute angle), and BC = x.

Since two angles are same therefore triangle ABC is an isosceles triangle and side AB and BC are congruent.

$AB=BC=x$

According to Law of cosine

$b^2=a^2+c^2-2ac\cos B$

$b^2=x^2+x^2-2(x)(x)\cos \beta$

$b^2=2x^2-2x^2\cos \beta$

$b^2=2x^2(1-\cos \beta)$

$\sqrt{2x^2(1-cos\beta)}$

Therefore the length of b is $\sqrt{2x^2(1-cos\beta)}$ .

6 0

2 years ago