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KengaRu [80]
3 years ago
15

Ethyl propanoate can be prepared by the reaction of ethanoic acid with propanol. B) ethanoic acid with isopropanol. C) ethanoyl

chloride with propanol. D) propanoyl chloride with ethanol. E) acetic anhydride with propanol.
Chemistry
1 answer:
Virty [35]3 years ago
4 0

Answer: Option D

Explanation:

Ester is prepared by esterification reaction between Carboxylic acid and alcohol

And from acid derivatives like acid chloride, anhydride & amide etc.

Here A gives propyl ethanoate by Esterification

B gives isopropyl ethanoate by Esterification

C gives propyl ethanoate by Acylation of alcohol

D gives ethyl propanoate by Acylation of Alcohol

E gives like C.

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For the following reaction, KP = 0.455 at 945°C: At equilibrium, is 1.78 atm. What is the equilibrium partial pressure of CH4 in
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Answer:

See explanation below

Explanation:

The question is incomplete. However, here's the missing part of the question:

<em>"For the following reaction, Kp = 0.455 at 945 °C: </em>

<em>C(s) + 2H2(g) <--> CH4(g). </em>

<em>At equilibrium the partial pressure of H2 is 1.78 atm. What is the equilibrium partial pressure of CH4(g)?"</em>

With these question, and knowing the value of equilibrium of this reaction we can calculate the partial pressure of CH4.

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*: You should note that we don't use Carbon here, because it's solid, and solids and liquids do not contribute in the expression of equilibrium, mainly because their concentration is constant and near to 1.

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