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nikdorinn [45]
3 years ago
10

Commercial scuba divers use tanks filled with a mixture of gases known as Trimix on very long, deep dives. Trimix is composed of

70% nitrogen, 10% oxygen and 20% helium. The total pressure of the Trimix inside a certain tank at the beginning of the dive is 118.4 atm. A. What is the partial pressure of the oxygen in the tank?
Chemistry
1 answer:
gulaghasi [49]3 years ago
7 0

Answer:

Partial pressure of O = 11.84 atm

Explanation:

To solve the excersise we think in the partial pressure law with mole fraction.

Mole fraction of gas = Partial pressure of gas / Total pressure

We have data of all the mole fractions:

  • 0.70 N
  • 0.10 O
  • 0.20 H

Let's find out the partial pressure of oxygen in the tank. We replace data in the formula:

0.10 = Partial pressure of gas / 118.4 atm

0.10 . 118.4 atm = Partial pressure of gas → 11.84 atm

If we determine all the partial pressures:

0.70 . 118.4 atm = 82.88 atm → Partial pressure N

0.20 . 118.4 atm = 23.68 atm → Partial pressure He

We can determine the partial pressure of the trimix.

Sum of partial pressures of each gas = Total pressure of the mix

11.84 atm + 82.88 atm + 23.68 atm = 118.4 atm

(A way to see, if our operations were ok)

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What is the empirical formula? A compound is used to treat iron deficiency in people. It contains 36.76% iron, 21.11% sulfur, an
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Answer: The empirical formula of the compound is Fe_1S_1O_4

Explanation:

Empirical formula is defined formula which is simplest integer ratio of number of atoms of different elements present in the compound.

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Percentage of sulfur in a compound = 21.11 %

Percentage of oxygen in a compound = 42.13 %

Consider in 100 g of the compound:

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Mass of iron in 100 g of compound = 21.11 g

Mass of iron in 100 g of compound = 42.13 g

Now calculate the number of moles each element:

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Divide the moles of each element by the smallest number of moles to calculated the ratio of the elements to each other

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For sulfur element = \frac{0.658 mol}{0.658 mol}=1

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So, the empirical formula of the compound is Fe_1S_1O_4

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