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3 years ago

Calculate h30+ for a 8.86*10^3 hbr solution

Chemistry

1 answer:

Mademuasel [1]3 years ago

3 0

[H₃O⁺] = 8.86 x 10³ M

<h3>Further explanation</h3>

The dissociation of water :

H₂O(l)⇒H⁺+OH⁻

Hydrogen ions H⁺ bond with H₂O to form H₃O⁺ ions(hydronium ion)

When acid(Hbr acid) is in the presence of water(dissociates), the H⁺ ions bond with water molecules to form hydronium, the reaction :

HBr(aq)+H₂O→H₃O+(aq)+Br−(aq

So Ionization of HBr :

$\tt HBr\rightarrow H_3O^++Br^-$

[HBr]= 8.86 x 10³,

From equation ratio [H₃O⁺] : HBr = 1 : 1, so

$\tt [H_3O^+]=8.86\times 10^3$

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4 years ago

An atom has a diameter of 2.50 Å and the nucleus of that atom has a diameter of 9.00×10−5 Å . Determine the fraction of the volu

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The fraction of the volume of the atom that is taken up by the nucleus is $4.6656\times 10^{-14}$ .

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Radius of the atom ,r = 0.5 d=0.5 × 2.50 Å = 1.25Å

Volume of the sphere= $\frac{4}{3}\pi r^3$

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Diameter of the nucleus ,d' = $9.00\times 10^{-5}\AA$

Radius of the nucleus ,r' = 0.5 d'= $0.5\times 9.00\times 10^{-5}\AA=4.5\times 10^{-5}\AA$

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Dividing [2] by [1]

$\frac{V'}{V}=\frac{\frac{4}{3}\pi r'^3}{\frac{4}{3}\pi r^3}$

$=\frac{r'^3}{r^3}=\frac{(4.5\times 10^{-5}\AA)^3}{(1.25 \AA)^3}$

$\frac{V'}{V}=4.6656\times 10^{-14}$

The fraction of the volume of the atom that is taken up by the nucleus is $4.6656\times 10^{-14}$ .

Diameter of the proton ,d = $1.72\times 10^{-15} m = 1.72\times 10^{-13} cm$

1 m = 100 cm

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Volume of the sphere= $\frac{4}{3}\pi r^3$

Volume of atom = V

$V=\frac{4}{3}\times 3.14\times (8.6\times 10^{-14} cm)^3=2.664\times 10^{-39}cm^3$

Mass of proton, m = 1.0073 amu = $1.0073\times 1.66054\times 10^{-24} g$

$1 amu = 1.66054\times 10^{-24} g$

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4 years ago

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Here we have get the group which has the lowest electronegativity in a period among the given groups.

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The electronegativity is defined as a measure of the tendency of an atom in a molecule to attract the electrons involved in the chemical bond formation.

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