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sertanlavr [38]
3 years ago
13

Calculate h30+ for a 8.86*10^3 hbr solution

Chemistry
1 answer:
Mademuasel [1]3 years ago
3 0

[H₃O⁺] = 8.86 x 10³ M

<h3>Further explanation</h3>

The dissociation of water :

H₂O(l)⇒H⁺+OH⁻

Hydrogen ions H⁺ bond with H₂O to form H₃O⁺ ions(hydronium ion)

When acid(Hbr acid) is in the presence of water(dissociates), the H⁺ ions bond with water molecules to form hydronium, the reaction :

HBr(aq)+H₂O→H₃O+(aq)+Br−(aq

So Ionization of HBr :

\tt HBr\rightarrow H_3O^++Br^-

[HBr]= 8.86 x 10³,

From equation ratio [H₃O⁺] : HBr = 1 : 1, so

\tt [H_3O^+]=8.86\times 10^3

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<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is 72 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

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The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[1\times (\Delta H_1)]+[2\times (-\Delta H_2)]+[2\times (\Delta H_3)]

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\Delta H^o_{rxn}=[(1\times (-1184))+(2\times -(-234))+(2\times (394))]=72kJ

Hence, the \Delta H^o_{rxn} for the reaction is 72 kJ.

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