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Sonja [21]
2 years ago
7

The valency of both Oxygen and magnesium is 2 give reason ​

Chemistry
1 answer:
lidiya [134]2 years ago
7 0

Answer:

<em>the <u>valency of an element</u> is its combining capacity that is the number of electrons it requires to lose, gain or share in order to become neutral.</em>

[ An element can become neutral if it completes it's octet. That is if an element has 8 electrons in it'd outermost shell then it is considered neutral ]

  • The valence of Magnesium is 2 because it requires to lose 2 electrons to become neutral.

  • whereas, the valence of Oxygen is 2 because it needs to gain 2 electrons to become stable.

Hence they both have the same valence.

One may say that oxygen's valence is -2 while that of Magnesium is + 2. It's meaning is still the same but "-" sign indicates that oxygen will be gaining electrons in the process of becoming stable.

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If the empirical formula of a compound is C2H5 and the Molecular mass is 87g/mol what is the molecular formula?
frez [133]
C6H15, C2H5 has a molar mass of 29g/mol. 87 divided by 29 is 3. Then multiply each element subscript by 3
6 0
3 years ago
For each of the salts below, match the salts that can be compared directly, using Ksp values, to estimate solubilities.
Anni [7]

Answer:

1 - Salts required  that can be compared directly, using Ksp values, to estimate solubilities for copper (II) sulfide are - CaSO_3 (Option b) ,BaCrO_4 (Option c) and CaS (Option d)

2 - Salts  that can be compared directly, using Ksp values, to estimate solubilities for zinc hydroxide are - Mg(OH)_2 (Option a)

Explanation:

K_s_p values can be used to compare the solubility of salts that produce ions in a 1:1 ratio.

  1. CuS {copper (II)sulfide} dissociates with ions in ratio 1:1 .

Because the salts CaSO_3 , BaCrO_4 and CaS  have a 1:1 ion ratio, the solubilities of options b, c, and d can be compared to salt 1.

K_s_p Values can be used to compare the solubility of salts that produce ions in a 1:2 or 2:1 ratio.

  2. Zn(OH)_2 dissociates into ions in ratio 1:2 .

Because the ions in the salt Mg(OH)_2 are in a 1:2 ratio, the solubility of salt 2 can be compared to that of salt 'a'.

Hence , Salt 1 is matched with options b , c , d.

              Salt 2 is matched with option a.

4 0
2 years ago
Suppose that 0.48 g of water at 25∘C∘C condenses on the surface of a 55-gg block of aluminum that is initially at 25∘C∘C. If the
GarryVolchara [31]

Answer : The final temperature of the metal block is, 25^oC

Explanation :

heat_{absorbed}=heat_{released}

As we know that,  

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]         .................(1)

where,

q = heat absorbed or released

m_1 = mass of aluminum = 55 g

m_2 = mass of water = 0.48 g

T_{final} = final temperature = ?

T_1 = temperature of aluminum = 25^oC

T_2 = temperature of water = 25^oC

c_1 = specific heat of aluminum = 0.900J/g^oC

c_2 = specific heat of water= 4.184J/g^oC

Now put all the given values in equation (1), we get

55g\times 0.900J/g^oC\times (T_{final}-25)^oC=-[0.48g\times 4.184J/g^oC\times (T_{final}-25)^oC]

T_{final}=25^oC

Thus, the final temperature of the metal block is, 25^oC

6 0
3 years ago
Consider the following reaction:C2H4(g) + F2(g) -----------&gt; C2H4F2(g) Delta H = -549 kJEstimate the carbon-fluorine bond ene
frutty [35]

Answer:

Bond energy of carbon-fluorine bond is 485 kJ/mol

Explanation:

Enthalpy change for a reaction,  is given as:

\Delta H_{rxn}=\sum [n_{i}\times (E_{bond})_{i}]-\sum [n_{j}\times (E_{bond})_{j}]

Where (E_{bond})_{i}  and (E_{bond})_{j} represents average bond energy in breaking "i" th bond and forming "j" th bond respectively.n_{i} and n_{j} are number of moles of bond break and form respectively.

In this reaction, one mol of C=C, four moles of C-H and one mol of F-F bonds are broken. One mol of C-C bond, four moles of C-H bonds and two moles of C-F bonds are formed

So, -549kJ=(1mol\times 614kJ/mo)+(4mol\times E_{C-H})+(1mol\times 154kJ/mol)-(1mol\times 347kJ/mol)-(4mol\times E_{C-H})-(2mol\times E_{C-F})

or, -549kJ=(1mol\times 614kJ/mo)+(1mol\times 154kJ/mol)-(1mol\times 347kJ/mol)-(2mol\times E_{C-F})

or, E_{C-F}=485kJ/mol

So bond energy of carbon-fluorine bond is 485 kJ/mol

8 0
3 years ago
I NEED HELP FAST !The density of aluminum is 2.70 g/cm3. How large a cube, in cm3, would contain 2.00 x 10^24 atoms of aluminum?
IceJOKER [234]

Explanation:

2.70 times 2.00 times 10...24=

4 0
3 years ago
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