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3 years ago

How is current transferred from the moving armature to the rest of the circuit in an alternating current generator

1 answer:

5 0

<span>In an alternating current generator, slip rings and brushes allow current to travel from the moving armature to the rest of the circuit.</span>

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The average distance between nitrogen and oxygen atoms is 115 pm in a compound called nitric oxide. what is this distance in cen

e-lub [12.9K]

<span>pm stands for picometer and picometers are units which can be used to measure really tiny distances. One picometer is equal to 10^{-12} meters. We know that one centimeter is equal to 10^{-2} m so there are 10^2 cm per meter. We can change the distance d = 115 pm to units of centimeters. d = (115 pm) x (10^{-12}m / pm) x (10^2 cm / m) d = 115 x 10^{-10} cm = 1.15 x 10^{-8} cm The distance in centimeters is 1.15 x 10^{-8} cm</span>

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3 years ago

HELP!!! Which element has 6 energy levels and 8 valence electrons?

Art [367]

Answer:

OXYGEN

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3 years ago

g Ethanol boils at 78.4 °C with \DeltaΔHvap = 38.6 kJ/mol. A 0.200-mol sample of ethanol is heated from some colder temperature

andrezito [222]

Answer:

8.77 kilo Joules will be the total amount of heat required for both the heating and the vaporizing.

Explanation:

Moles of ethanol of ethanol = 0.200 mol

Heat required to heat 0.200 moles of ethanol = Q = 1.05 kJ

Enthalpy of vaporization of ethanol = $\Delta H_{vap}=38.6 kJ/mol$

Heat required to vaporize 0.200 moles of ethanol = Q'

$Q'=\Delta H_{vap}\times 0.200 mol=38.6 kJ/mol\times 0.200 mol=7.72 kJ$

Total heat required to fore heating and the vaporizing :

= Q + Q' = 1.05 kJ + 7.72 kJ = 8.77 kJ

8.77 kilo Joules will be the total amount of heat required for both the heating and the vaporizing.

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4 years ago

Sean is using rates of deposition to estimate the age of a sediment deposit in the Great Smoky Mountains National Park in Gatlin

Ipatiy [6.2K]

Answer:

sry i cant i to dubm need points tho

Explanation:

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3 years ago

Carbon disulfide burns in oxygen to yield car- bon dioxide and sulfur dioxide according to the chemical equation cs2(l) 3 o2(g)

vampirchik [111]

Answer: Oxygen is the limiting reagent.

Explanation: $CS_2(l)+3O_2(g)\rightarrow CO_2(g)+2SO_2(g)$

As can be seen from the given balanced equation:

3 moles of $O_2$ reacts with 1 mole of $CS_2$

1.52 moles of $O_2$ reacts with= $\frac{1}{3}\times 1.52=0.51moles$ of $CS_2$

Thus $O_2$ is the limiting reagent as it limits the formation of products. (0.91-0.51)= 0.40 moles of $CS_2$ will remain as such and thus $CS_2$ is an excess reagent.

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3 years ago