Answer:
a. 0.5 mol
b. 1.5 mol
c. 0.67
Explanation:
Fe3+ + SCN- -----> [FeSCN]2+
a. The ratio of the product to Fe3+ is 1:1. Meaning that if 0.5 mol of product was produced up then 0.5 mol of Fe3+ was used. Leaving 0.5 mol remaining at equilibrium
b. The ratio of the product to SCN= is 1:1. Meaning that if 0.5 mol of product was produced up then 0.5 mol of SCN- was used. Leaving 1.5 mol remaining at equilibrium
c. KC = 0.5/(0.5*1.5) = 0.67
A.) 1.
b.) 3
c.) 2
I hope this helps.
Answer:
The chemical equation needs to be balanced so that it follows the law of conservation of mass.
Explanation:
Answer:
50 mL
Explanation:
In case of titration , the following formula is used -
M₁V₁ = M₂V₂
where ,
M₁ = concentration of acid ,
V₁ = volume of acid ,
M₂ = concentration of base,
V₂ = volume of base .
from , the question ,
M₁ = 0.50M
V₁ = 100 mL
M₂ = 1.0M
V₂ = ?
Using the above formula , the volume of base , can be calculated as ,
M₁V₁ = M₂V₂
substituting the respective values ,
0.50M * 100 mL = 1.0M * V₂
V₂ = 50 mL
Answer : 0.0392 grams of Zn metal would be required to completely reduced the vanadium.
Explanation :
Let us rewrite the given equations again.
On adding above equations, we get the following combined equation.
We have 12.1 mL of 0.033 M solution of VO₂⁺.
Let us find the moles of VO₂⁺ from this information.
From the combined equation, we can see that the mole ratio of VO₂⁺ to Zn is 2:3.
Let us use this as a conversion factor to find the moles of Zn.
Let us convert the moles of Zn to grams of Zn using molar mass of Zn.
Molar mass of Zn is 65.38 g/mol.
We need 0.0392 grams of Zn metal to completely reduce vanadium.
