What point is halfway between (3, -1) and (8,-6)?
2 answers:
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1) find slope. when its perpendicular, It will be a negative reciprocal to the given slope so m1= -1/m1
m=-1
2)
y =-1x+b
(-3)=-1(2)+b
-3=-2+b
b=-1
3) y=-1x-1
hope I helped!
m=-1
2)
y =-1x+b
(-3)=-1(2)+b
-3=-2+b
b=-1
3) y=-1x-1
hope I helped!