To find the solution, we use the substitution method.
x+y=-1
<span>x-3y=11
</span>
x+y = -1-y
-y
x = -1-y
Now apply the value of x into the other equation.
x-3y=11
-1-y-3y = 11
Combine like terms
-4y -1 = 11
+1 +1
-4y = 12
-4y = 12
-4y/-4 = 12/-4
y = -3
Now, apply the value of Y to one equation to find x.
y = -3
x -3 = -1
+3 +3
x= 2
Now we have the value for both, x and y.
x = 2
y =-3
Final answer: A. <span>(2, −3)</span>
Answer:
The vertex of the function 
is 
Step-by-step explanation:
I've graphed this on desmos for a visual
You can buy 7 flats of flowers. this is because 10.99 is close to 11.00, and 7 x 11 is 77. and you cant do 77 + 11 to get less then 80.
the answer: 7 flats of flowers
hope it helps :)
Remember x is x and f(x) is same thing as y.
f(5) = 4
It is same thing as saying, when x = 5, y aka f(x) should be 4. Aka the point (5,4)
Let’s look at D, if x =5 then f(x)=5? No, it should equal 4. So this is wrong. It is also not linear. So NOT D
Lets look at C, if x =5 then
1/5(5)+3 =
5/5 + 3 =
1+3 =
4
So, f(x) aka y = 4. Is this correct? Yes when x =5, y indeed should equal 4, but it is not linear. So NOT C
Lets look at B, if x=5 then,
2^5 -28 =
32 - 28 =
4
So, f(x) aka y = 4. Is this correct? Yes when x =5, y indeed should equal 4, AND it is linear SO THE ANSWER IS B
Check A too, it gets y=14 so thats wrong as it is not 4.
In pure translation or in roll without slip?
In pure translation, just use Fnet = m*a. Fnet = 7.5 Newtons
In roll without slip it has effectively more inertia than 5 kilograms. The effective inertia can be found as:
m_effective = m + I/r^2
For a uniform solid sphere, I = 2/5*m*r^2
So m_effective = 7/5*m
To make a 5 kg bowling ball accelerate at 1.5 m/s^2 in roll without slip, it requires Fnet = 10.5 Newtons, and this ASSUMES that all forces causing the net force on it have lines of action through its center of mass (most common case).
i hope this is what ur looking for
