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KIM [24]
3 years ago
11

The gravitational force between Earth and the Sun is a two-way force. Both the planet and the Sun attract each other. However, E

arth revolves around the Sun rather than the Sun revolving around Earth. Which statement BEST explains the orbit of the Earth around the Sun?
A) The Sun is at the center of the Solar System.
B) The Sun’s mass is much greater than Earth’s.
C) Earth rotates about its axis, but the Sun does not.
D) Other planets also try to move the Sun around them
Physics
1 answer:
kumpel [21]3 years ago
5 0

Answer:

b

Explanation:

The Sun exert a gravitational pull on the earth just as the earth exert gravitational pull on the sun but the sun mass is bigger than the earth, hence the earth orbits round the sun in elliptical orbit due to the greater gravitational pull of the sun.

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When light reflects from a surface, there is a change in its
alexandr402 [8]
The answer is: none of the above.

Explanation:

When light reflects from a surface, the frequency, wavelength, and speed do not change. They remain the same.
6 0
3 years ago
I need help ASAP please :)
rusak2 [61]

Density offers a convenient means of obtaining the mass of a body from its volume or vice versa; the mass is equal to the volume multiplied by the density (M = Vd), while the volume is equal to the mass divided by the density (V = M/d).

M = V d

M = 1.4 * 2 = 2.8 kg

7 0
2 years ago
Calculate the de broglie wavelength (in picometers) of a hydrogen atom traveling at 440 m/s.
Aleonysh [2.5K]

De broglie wavelength, \lambda = \frac{h}{mv}, where h is the Planck's constant,  m is the mass and v is the velocity.

h = 6.63*10^{-34}

Mass of hydrogen atom,  m = 1.67*10^{-27}kg

v = 440 m/s

Substituting

   Wavelength \lambda = \frac{h}{mv} = \frac{6.63*10^{-34}}{1.67*10^{-27}*440} = 0.902 *10^{-9}m = 902 *10^{-12}m

1 pm = 10^{-12}m\\ \\ So , \lambda =902 pm

So  the de broglie wavelength (in picometers) of a hydrogen atom traveling at 440 m/s is 902 pm

7 0
3 years ago
A ball is thrown upward at a 45° angle. Inthe absence of air resistance, the ballfollows aA. tangential curve.B. sine curve.C. p
Evgesh-ka [11]

As ball is projected up in air at an angle of 45 degree without any air resistance

Let the initial speed will be v

now we will have

In x direction

v_x = v cos45

in y direction

v_y = vsin45

now displacement in x direction

x = (vcos45)t + 0

displacement in y direction

y = (vsin45)t - \frac{1}{2}gt^2

now from above two equations we have

y = (vsin45)\frac{x}{vcos45} - \frac{1}{2}g(\frac{x}{vcos45})^2

y = xtan45 - \frac{1}{2v^2cos^245}gx^2

so above equation is a quadratic equation and hence it will be a parabolic curve

so correct answer will be

<em>C. parabolic curve.</em>

8 0
3 years ago
What is the kinetic energy of a 1.40 kg discus with a speed of 22.5 m/s?
Oksana_A [137]
Kinetic energy = (1/2) (mass) (speed)²

                         = (1/2) (1.4 kg) (22.5 m/s)²

                         =    (0.7 kg)  (506.25 m²/s² )

                         =          354.375  kg-m²/s²  =  354.375 joules .

This is just the kinetic energy associated with a 1.4-kg glob of
mass sailing through space at 22.5 m/s.  In the case of a frisbee,
it's also spinning, and there's some additional kinetic energy stored
in the spin. 
8 0
3 years ago
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