Answer:
m = 
x,
graph of x vs m
Explanation:
For this exercise, the simplest way to determine the mass of the cylinder is to take a spring and hang the mass, measure how much the spring has stretched and calculate the mass, using the translational equilibrium equation
F_e -W = 0
k x = m g
m = x
We are assuming that you know the constant k of the spring, if it is not known you must carry out a previous step, calibrate the spring, for this a series of known masses are taken and hung by measuring the elongation (x) from the equilibrium position, with these data a graph of x vs m is made to serve as a spring calibration.
In the latter case, the elongation measured with the cylinder is found on the graph and the corresponding ordinate is the mass
Answer:
Speed, u = 29.4 m/s
Explanation:
Given that, A ball thrown straight up climbs for 3.0 sec before falling, t = 3 s
Let u is speed with which the ball is thrown up. When the ball falls, v = 0
Using first equation of motion as :
v = u + at
Here, a = -g
So, u = g × t
u = 29.4 m/s
So, the speed with which the ball was thrown is 29.4 m/s. Hence, this is the required solution.
Answer:
D
Explanation:
Now we know that Force is the rate of change of momentum meaning
F= mv/t
But
mv/t = Ke
v/t = ke/m
a= ke/m
Where a is acceleration
K is constant of proportionality of tension on a spring
e is the extension substended by a string.
From the formula of acceleration we can see that as mass decreases acceleration increases so we can see that m = 1
We would have a maximum value of acceleration.
Answer: 510 m/s
Explanation: specific gravity of steam is 18/29 = 0.620
It is the ratio of the density of steam over density of water
400m3/s of steam =
400m3ms * 0.620 of water
= 248m3/s of water
Total flow rate Q = 248 + 7 = 255m3/s
Using Q = AV
Where A is area and V is velocity
V = Q/A
V = 255/0.5 = 510m/s
The answers to your questions are as written below:
- The objects that represents a negatively charged particle is : Image B
- The object that represents a positively charged molecule is : Image A
- The object that represents an uncharged molecule is : Image C
- The object the will not move when in an electric fied is : Image C
<h3>Different types of charges molecules</h3>
A negatively charged molecule move inwards when placed in an electric field while positively charged molecule placed in a electric field will move outwards the electric field.
A neutral/uncharged molecule will remains still when placd in an elctric field due to the absence of charges.
Hence we can concude that the answers to your questions are as listed above.
Learn more about electric charges :brainly.com/question/857179
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attached below is the missing image
