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KIM [24]
3 years ago
11

The gravitational force between Earth and the Sun is a two-way force. Both the planet and the Sun attract each other. However, E

arth revolves around the Sun rather than the Sun revolving around Earth. Which statement BEST explains the orbit of the Earth around the Sun?
A) The Sun is at the center of the Solar System.
B) The Sun’s mass is much greater than Earth’s.
C) Earth rotates about its axis, but the Sun does not.
D) Other planets also try to move the Sun around them
Physics
1 answer:
kumpel [21]3 years ago
5 0

Answer:

b

Explanation:

The Sun exert a gravitational pull on the earth just as the earth exert gravitational pull on the sun but the sun mass is bigger than the earth, hence the earth orbits round the sun in elliptical orbit due to the greater gravitational pull of the sun.

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The vaule of the g constant (the acceleration of all objects due to gravity)on earth is
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 The answer is:  " \frac{9.8 m}{s^2}" .
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3 years ago
A sample of a gas has a volume of 639 cm3 when the pressure is 75.9 kPa. What is the volume of the gas when the pressure is incr
const2013 [10]

Answer:

388 cm^3

Explanation:

For this problem, we can use Boyle's law, which states that for a gas at constant temperature, the product between pressure and volume remains constant:

pV=const.

which can also be rewritten as

p_1 V_1 = p_2 V_2

In our case, we have:

p_1 = 75.9 kPa is the initial pressure

V_1 = 639 cm^3 is the initial volume

p_2 = 125 kPa is the final pressure

Solving for V2, we find the final volume:

v_2 = \frac{p_1 V_1}{p_2}=\frac{(75.9)(639)}{125}=388 cm^3

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3 years ago
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3 years ago
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HOW MANY LICKS DOES IT TAKE TO GET TO THE CENTER OF A TOOTSIE POP?​
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An airplane has an effective wing surface area of 17.0 m2 that is generating the lift force. In level flight the air speed over
olga_2 [115]

To solve this problem it is necessary to apply the equations given from Bernoulli's principle, which describes the behavior of a liquid moving along a streamline. Mathematically this expression can be given as,

P_1 + \frac{1}{2}\rho*v_1^2 + P_2 + \frac{1}{2}*\rho*v_2^2=0

Where,

P_i = Pressure at each state

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v_i = Velocity

Re-organizing the expression we can get that

P_1 - P_2 = \frac{1}{2}\rho (v_2^2 - v_1^2)

Our values are given as

v_1 = 40m/s

v_2 = 55m/s

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Replacing we have,

P_1 -P_2 = \frac{1}{2}*1.2*(55^2-40^2)

P_1 - P_2 = 855Pa

If we consider that there is a balance between the two states, the Force provided by gravity is equivalent to the Support Force, therefore

F_l = F_g

Here the lift force is the product between the pressure difference previously found by the effective area of the aircraft, while the Force of gravity represents the weight. There,

F_g = W

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Equating,

(P_1 - P_2)*A = W

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Therefore the weight of the plane is 14535N

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3 years ago
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