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mr Goodwill [35]
3 years ago
13

Do solar panels create enough energy to power the car throughout the day?

Physics
1 answer:
JulijaS [17]3 years ago
5 0

Answer:

Yes, but only if it's sunny.

Explanation:

As you know, solar panels generate energy through the sun's rays of light (better known as sunlight). Therefore, as long as the sun is shining high in the sky, the car will generate electricity and be able to function. If this vehicle was only powered by solar panels, it would not function during the night, in cloudy areas, and/or in dark places (such as parking garages or home garages).

Hope this helps!

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GIVING BRAINLIEST FIVE STARS AND 25 POINTS!
Ne4ueva [31]

Engines can overheat for many reasons. In general, it's because something's wrong within the cooling system and heat isn't able to escape the engine compartment. The source of the issue could include a cooling system leak, faulty radiator fan, broken water pump, or clogged coolant hose.

Hope it helps! Have a nice day or night!

4 0
3 years ago
Read 2 more answers
Afootball of mass 550g is at rest on the ground the football is kicked with a force of 108 newton the footballers boot is in con
d1i1m1o1n [39]

If "0.3 minute" is correct, then it's 9,543,272 Joules.

If it's supposed to say "0.3 SECOND", then the KE is 2,651 Joules.

6 0
3 years ago
Which of the following is an example of rolling friction?
il63 [147K]

Answer:

O bike tires on the road as you ride

Explanation:

is the rolling friction

7 0
3 years ago
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250 W 12 km/h<br>4. Convert yoor answer from 3 to meters per second.​
taurus [48]

Answer: 3.33 m/s

Explanation:

Assuming the questions is to convert  12 km/h to meter per second (m/s), let's begin:

In order to make the conversion, we have to know the following:

1 km=1000 m

And:

1 h=3600 s

Keeping this in mind, we can make the conversion:

12 \frac{km}{h} \frac{1000 m}{1 km} \frac{1h}{3600 s}

Then:

12 \frac{km}{h}= 3.33 \frac{m}{s}

5 0
3 years ago
Calculate the potential energy of a +1.0μC point charge sitting 0.1m from a -5.0μC point charge.
AfilCa [17]

Answer:

P.E.      =   -0.449 J

Explanation:

Potential energy of a charge particle in any electrostatic field is defined as the amount of work done ( in negative ) to bring that charge particle from any position to a new position r.

Now Potential energy is defined by this formula,

P.E. = k q₁ q₂/ r

where P.E. is the potential energy.

k = 1/( 4πε₀) = 8.99 × 10⁹ C²/ ( Nm²)

q₁ = charge of one particle = +1.0μC

q₂ = charge of another particle = -5.0μC

r = distance = 0.1 m

Now , P.E. = 8.99 × 10⁹C²/ ( Nm²) * ( -5.0 × 10⁻⁶ C ) × ( 1 × 10⁻⁶ C ) / 0.1 m

          P.E.      =  -0.449 J

8 0
3 years ago
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