Answer:

Explanation:
As we know that sound level is given as

so here we have

now we can take anti log both sides

so we have

so above is the expression for the intensity of sound in terms of reference intensity and sound level
It sounds like a special relativity question but I need more info for a total answer. But remember it's length in the lab frame is
L•sqrt(1-(v/c)^2) where L is the rest length, v is its velocity magnitude and c is the speed of light. Sqrt is the square root (I'm on a phone so I can't see the math equation editor)
Answer:
1988 m
Explanation:
Range of a projectile
R = U²sin2∅/g...................... Equation 1
Where R = Range, U = Initial velocity, g = acceleration due to gravity, ∅ = Angle of projection.
Given: U = 150 m/s, ∅ = 60°
Constant: g = 9.8 m/s².
Substitute these values into equation 1
R = 150²(sin60°)/9.8
R = 22500(0.866)/9.8
R = 1988 m
Hence the Range of the projectile is 1988 m
Answer:
I believe it's True! Brainliest??
Explanation: Hope you have a great day :)