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Xelga [282]
3 years ago
15

Two non-simultaneous events have an equal likelihood of occurring (50%). If the events are independent of each other, what is th

e probability that they will both occur?
Mathematics
2 answers:
BARSIC [14]3 years ago
7 0
There are 4 possibilities:

1) No event happens
2) event A happens, not event B
3) event B happens, not event A
4) both events happen

seeing as there is a 50% chance of either event happening, I would assume that all 4 possibilities have an equal chance of happening

so if there are 4 events, then each one is 25% likely.

So the probability if them both occurring is 25%

I think
Naily [24]3 years ago
4 0

Answer:

I got 25% on edmentum

Step-by-step explanation:

You might be interested in
Find all x-values for which f ( x ) = 2 for the function below.
Angelina_Jolie [31]

Answer:

<h3>x = -3</h3>

Step-by-step explanation:

First let us get the equation of the coordinates

y-y0 = m(x-x0)

Using the coordinates ( - 3, 2 ), ( - 1, 0 )

m = 0-2/-1-(-3)

m = -2/2

m = -1

Substitute m = -1 and (-1, 0) into the formula

y - 0 = -1(x+1)

y = -x-1

f(x) = -x-1

Since f(x) = 2

2 = -x-1

-x = 2+1

-x = 3

x = -3

Hence the value of x is -3

8 0
3 years ago
How many ways can six of the letters of the word ALGORITHM be selected 8. How many ways can the letters of the word ALGORITHM be
SCORPION-xisa [38]
<h2>Answer with explanation:</h2>

The number of letters in word "ALGORITHM" = 9

The number of combinations to select r things from n things is given by :-

C(n,r)=\dfrac{n!}{r!(n-r)!}

Now, the number of combinations to select 6 letters from 9 letters will be :-

C(9,8)=\dfrac{9!}{6!(9-6)!}=\dfrac{9\times8\times7\times6!}{6!\times3!}=84

Thus , the number of ways can six of the letters of the word ALGORITHM=84

The number of ways to arrange n things in a row :n!

So, the number of ways can the letters of the word ALGORITHM be arranged in a be seated together in the row :-

9!=362880

If GOR comes together, then we consider it as one letter,  then the total number of letters will be = 1+6=7

Number of ways to arrange 9 letters if "GOR" comes together :-

7!=5040

Thus, the number of ways to arrange 9 letters if "GOR" comes together=5040

3 0
3 years ago
If f(x)=2x^6+x^5+32x+32, is (x+2) a factor of f(x).
Angelina_Jolie [31]

Answer:

No

Step-by-step explanation:

By the factor theorem if (x + 2) is a factor of f(x) then f(- 2) = 0

f(- 2)

= 2(-2)^{6} + -2)^{5} + 32(- 2) + 32

= 2(64) - 32 - 64 + 32

= 128 - 32 - 64 + 32

= 64 ≠ 0

Hence (x + 2) is not a factor of f(x)

4 0
3 years ago
Read 2 more answers
I can't figure out how to do this problem. Could somebody help me?
Verizon [17]

start by plugging in the value you already have, in this case, 5 for y.

-4x-3(5)=17

-4x-15=17

-4x=32

x=-8

however, since a is a+1, a would be 7 (making x 8)

also plz tell me if i read this wrong and it’s actually 1,5 rather than a+1 and 5 cause if i did i’m so sorry lol.

8 0
3 years ago
(2+2w)⋅4+9(w+3) please answer this I am very confused
defon

Answer:

17w+35

Step-by-step explanation:

(2+2w)⋅4+9(w+3)

Distribute the 4  and the 9

2*4 + 2w*4 +9*w+9*3

8+8w +9w +27

Combine like terms

8w+9w +8+27

17w +35

8 0
3 years ago
Read 2 more answers
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