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3 years ago

A toy store’s percent markup is 50%. The wholesale price of a model train is $77. Find the retail price.

Mathematics

2 answers:

Radda [10]3 years ago

5 0

It's original price was $38.50

Tpy6a [65]3 years ago

5 0

The answer would be 38.50$, hope this was helpful! (:

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if 3/4 of a cup of water fills 2/3 of a plastic container, how many containers can you fill with one cup of water?

Luda [366]

Answer:

1 cup of water will fill = $\frac{8}{9}$ of the plastic container.

Step-by-step explanation:

Given :

$\frac{3}{4}$ of a cup of water fills $\frac{2}{3}$ of a plastic container.

To find number of containers that can be filled with 1 cup of water, we will use unitary method.

if $\frac{3}{4}$ of a cup of water fills $\frac{2}{3}$ of a plastic container.

Then 1 cup of water will fill = $\frac{2}{3}\div \frac{3}{4}$ of a container.

Dividing fractions.

$\frac{2}{3}\div \frac{3}{4}$

Replacing division with multiplication by taking reciprocal of the divisor.

$\frac{2}{3}\times \frac{4}{3}$

Multiplying the numerators and denominators.

$\frac{2\times4}{3\times3}$

$\frac{8}{9}$

∴ 1 cup of water will fill = $\frac{8}{9}$ of the plastic container.

5 0

3 years ago

5+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B16x%5E%7B2%7D%20-37x-2%20%7D%3D4x" id="TexFormula1" title="\sqrt{16x^{2} -37x-2 }=

bonufazy [111]

Answer:

Step-by-step explanation:

$\sqrt{16x^2-37x-2} =4x-5\\squaring~ both~sides\\16x^2-37x-2=16x^2-40x+25 ~[(a-b)^2=a^2-2ab+b^2]\\16x^2-37x-2-16x^2+40x-25=0\\3x-27=0\\3(x-9)=0\\x-9=0\\x=9$

4 0

4 years ago

3x -2 > -11<br><br> (The > has an underscore under it)

user100 [1]

$3x-2\geq-11$

$3x\geq-9$

$x\geq-3$

$x\in[-3, \infty)$

Hope this helps.

7 0

3 years ago

A football is kicked from the ground and follows the graph of the function y = –t2 + 3t, where y represents height and t represe

vesna_86 [32]

Answer:

The height of the objects are the same after 2 seconds.

Step-by-step explanation:

In order to calculate at which time both objects have the same height we need to find the value of t that makes both equations equal. Therefore:

$-t^2 + 3t = -t + 4\\t^2 - 3t - t + 4 = 0\\t^2 - 4t + 4 = 0\\t_{1,2} = \frac{-(-4) \pm \sqrt{(-4)^2 - 4*1*4}}{2*1} = \frac{4 \pm \sqrt{16 - 16}}{2}\\t_{1,2} = \frac{4}{2} = 2$

The height of the objects are the same after 2 seconds.

8 0

3 years ago

For which equations below is x = –3 a possible solution? Check all that apply.

Tju [1.3M]

What are the options

3 0

3 years ago