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Lera25 [3.4K]
4 years ago
8

A double-displacement reaction occurs when the negative ion of me compound replaces the positive ion of the other compound to fo

rm two new compounds during a chemical reaction.
A. True
B. False
Chemistry
2 answers:
Lapatulllka [165]4 years ago
6 0

Answer: B. False

Explanation: A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

Example:

2NaOH(aq)+(NH_4)_2SO_4(aq)\rightarrow 2NH_4OH(aq)+Na_2SO_4(aq)

Thus as we can see sodium ion Na^+ is being replaced by ammonium ions  NH_4^+ and thus positive ions replace positive ions only and not negative ions.

serg [7]4 years ago
5 0

Answer:

False

Explanation:

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The daily output of stomach acid (gastric juice) is 1000 to 2000 mL. Prior to a meal, stomach acid (HCl) typically has a pH of 1
Semmy [17]

Answer:

B.) 2 HCl(aq) + CaCO₃(s) → CaCl₂(aq) + H₂O(l) + CO₂(g)

C.) 7.4 × 10² mL

D.) 2 HCl(aq) + Mg(OH)₂(aq) → MgCl₂(aq) + H₂O(l)

E.) 1.3 × 10³ mL

Explanation:

<em>The daily output of stomach acid (gastric juice) is 1000 to 2000 mL. Prior to a meal, stomach acid (HCl) typically has a pH of 1.49.</em>

We can calculate the concentration of H⁺ using the definition of pH.

pH = -log [H⁺]

[H⁺] = antilog -pH = antilog (-1.49) = 0.0324 M

Since HCl is a strong monoprotic acid, we can consider this to be the concentration of HCl as well.

<em>B.) One chewable tablet of the antacid Maalox contains 600 mg of CaCO₃. Enter the neutralization equation. Express your answer as a molecular equation including phases.</em>

The neutralization equation is:

2 HCl(aq) + CaCO₃(s) → CaCl₂(aq) + H₂O(l) + CO₂(g)

<em>C.) Given that one chewable tablet of the antacid Maalox contains 600 mg of CaCO₃, calculate the milliliters of stomach acid neutralized by two tablets of Maalox. Express the volume in milliliters to two significant figures.</em>

We can establish the following relations:

  • Each tablet has 600 mg (0.600 g) of CaCO₃.
  • The molar mass of CaCO₃ is 100.09 g/mol.
  • The molar ratio of HCl to CaCO₃ is 2:1.
  • The concentration of HCl is 0.0324 mol/L.

The mililiters of HCl that neutralize 2 tablets of Maalox are:

2Tablet.\frac{0.600gCaCO_{3}}{1Tablet} .\frac{1molCaCO_{3}}{100.09gCaCO_{3}} .\frac{2molHCl}{1molCaCO_{3}} .\frac{1000mLHCl}{0.0324molHCl} =7.4 \times 10^{2} mLHCl

<em>D.) The antacid milk of magnesia contains 400 mg of Mg(OH)₂ per teaspoon. Enter the neutralization equation. Express your answer as a molecular equation including phases.</em>

The neutralization equation is:

2 HCl(aq) + Mg(OH)₂(aq) → MgCl₂(aq) + H₂O(l)

<em>E.) Given that the antacid milk of magnesia contains 400 mg of Mg(OH)₂ per teaspoon, calculate the number of milliliters of stomach acid that are neutralized by 1 tablespoon of milk of magnesia. (1 tablespoon = 3 teaspoons.)Express the volume in milliliters to two significant figures.</em>

We can establish the following relations:

  • 1 tablespoon = 3 teaspoons
  • 1 teaspoon contains 400 mg (0.400 g) of Mg(OH)₂
  • The molar mass of Mg(OH)₂ is 58.32 g/mol.
  • The molar ratio of HCl to Mg(OH)₂ is 2:1.
  • The concentration of HCl is 0.0324 mol/L.

The mililiters of HCl that neutralize 1 tablespoon of milf of magnesia are:

1Tablespoon.\frac{3Teaspoon}{1Tablespoon} .\frac{0.400gMg(OH)_{2}}{1Teaspoon} .\frac{1molMg(OH)_{2}}{58.32gMg(OH)_{2}} .\frac{2molHCl}{1molMg(OH)_{2}} .\frac{1000mLHCl}{0.0324molHCl} =1.3 \times 10^{3} mLHCl

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3 years ago
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Natasha_Volkova [10]

Answer:

IT IS A METALLOID..

ANSWER BORON

3 0
3 years ago
Which activity most likely involves the direct use of saturated hydrocarbons?
Ugo [173]
I dont know but the options are: 
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4 years ago
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Diluting concentrated 1.74M acetic acid to prepare 200 ml of 8M stick solution. What volume of concentrated acid must be used
TiliK225 [7]
<h3>Answer:</h3>

43.5 mL

<h3>Explanation:</h3>

We are given;

  • Molarity of dilute acetic acid is 1.74 M
  • Volume of the solution that needs to be prepared is 200 mL
  • Molarity of the stock solution 8 M

We are required to determine the volume of acid that must be used.

  • We need to know the dilution formula;
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M1V1 = M2V2

Rearranging the formula;

V1 = M2V2 ÷ M1

   = (1.74 M × 200 mL) ÷ 8 M

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Therefore, the volume of the concentrated acid that must be added is 43.5 mL

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I think it is sand and gold.

4 0
3 years ago
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